SATHEE: Chemical and Ionic Equilibrium 2 Question 19

Chemical and Ionic Equilibrium 2 Question 19

19. For a sparingly soluble salt $A_{p} B_{q}$ , the relationship of its solubility product $(L_{S})$ with its solubility $(S)$ is

$(2001, 1 M)$

(a) $L_{s} = S^{p + q} \cdot p^{p} \cdot q^{q}$

(b) $L_{s} = S^{p + q} \cdot p^{q} \cdot q^{p}$

(d) $L_{s} = S^{p q} \cdot (p \cdot q)^{(p + q)}$

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Solution:

$A_{p} B_{q} ⇌ \underset{p S}{p A} + \underset{q S}{q B}$

$K_{sp} = (p S)^{p} (q S)^{q} = S^{(p + q)} \cdot p^{p} \cdot q^{q}$

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Chemical and Ionic Equilibrium 2 Question 19

19. For a sparingly soluble salt ApBq, the relationship of its solubility product (LS) with its solubility (S) is

Solution:

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19. For a sparingly soluble salt $A_{p} B_{q}$ , the relationship of its solubility product $(L_{S})$ with its solubility $(S)$ is