Chemical and Ionic Equilibrium 1 Question 39
41. If equilibrium constant for the reaction, $A_{2}+B_{2} \rightleftharpoons 2 A B$, is $K$, then for the backward reaction $A B \rightleftharpoons \frac{1}{2} A_{2}+\frac{1}{2} B_{2}$, the equilibrium constant is $\frac{1}{K}$.
$(1984,1 \mathrm{M})$
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Solution:
- It is $\frac{1}{\sqrt{K}}$.
