Atomic Structure 1 Question 26

2. If p is the momentum of the fastest electron ejected from a metal surface after the irradiation of light having wavelength λ, then for 1.5p momentum of the photoelectron, the wavelength of the light should be

(Assume kinetic energy of ejected photoelectron to be very high in comparison to work function)

(2019 Main, 8 April II)

(a) 49λ

(b) 34λ

(c) 23λ

(d) 12λ

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Answer:

Correct Answer: 2. (a)

Solution:

  1. The expression of kinetic energy of photo electrons,

KE=12mv2=EE0

When, KE»E0, the equation becomes,

KE=12mv2=E 12mv2=hcλp22m2=hcλ λ=hc×2m2×1p2λ1p2 E=hcλ= energy of incident light.  E0= threshold energy or work functions,  12mv2=12×(mv)2m2=12×p2m2

p= momentum =mv

As per the given condition,

λ2λ1=(p1p2)2

λ2λ=(p1.5×p)2=(23)2=49 λ2=49λ[λ1=λ p1=p]