Amines - Result Question 32
####34. Intermediates formed during reaction of
$ \underset{\text{ O }}{RCNH_2} \text{ with } Br_2 \text{ and } KOH \text{ are } $
(a) $RNHBr$ and $RCONHBr$
(b) $RNHCOBr$ and $RNCO$
(c) $RCONHBr$ and $RNCO$
(d) $RCONBr_2$
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Solution:
- (c) The mechanism of Hoffmann bromamide reaction is
(i) $RCONH_2+Br_2 \to RCONHBr+HBr$
(ii) $RCONHBr+HBr \xrightarrow{OH^{-}}$
$R-CO \ddot{N} Br+H_2 O$ (iii)
(iv)
(v) $R-\ddot{N}=C=O+2 KOH \to RNH_2+K_2 CO_3$
