Principles of Inheritance and Variation Question 52
52. At a particular locus, frequency of ’ $A$ ’ allele is 0.6 and that of ’ $a$ ’ is 0.4 . What would be the frequency of heterozygotes in a random mating population at equilibrium?
(a) 0.36
(b) 0.16
(c) 0.24
(d) 0.48
Show Answer
Answer : d
Hints & Solution
(d) The mathematical expression to calculate allele frequency can be given as $p+q=1$. Where $p$ represents the frequency of dominant allele and q represents the frequency of recessive allele. The bionomial expression of Hardy Weinberg’s law to calculate genotype frequency is $p^{2}+2 pq+q^{2}=1$ where $p^{2}=$ homozygous dominant $2 pq=$ heterozygous dominant $q^{2}=$ homozygous recessive. Frequency of heterozygous individuals $=2 \times 0.6 \times 0.4=0.48$.
