PERMUTATIONS AND COMBINATIONS - 4 (Simple Applications on nPr and nCr)

Important Results

1. Sum of digits in the unit place of all numbers formed by a1,a2an taken all at a time is given by (n1)!(a1+a2+..an) if repetition of digits is not allowe(d).

2. Sum of all the numbers which can be formed using the digits a1,a2an (repetition not allowed)

=(n1)!(a1+a2++an)(10n1)9=(n1)!( sum of digits) (1n times 11)

3. Number of whole number solutions (xi0i) (non-negative) of x1+x2+..xr=n is n1Cr1 Number of solutions of α+2β+3γ+.+qθ=n is

{ coefficient of xn in (1x)1(1x2)1(1x3)1(1xq)1 if zero is included  coefficient of xn in x1+2+.+q(1x)1(1x2)1.(1xq)1 if zero is not included 

Number and sum of divisors

4. Let N=apbqcr where a,b,c are primes &p,q,rZ+.

i. Number of divisors of N=(p+1)(q+1)(r+1)

Sum of divisors of N=(1+a+a2+ap)(1+b+b2+.bq)(1+c+c2+cr)

ii. Number of ways in which N can be resolved as a product of two factors is

{12(a+1)(b+1)(c+1) if N is not perfect square {12(a+1)(b+1)(c+1)+1} if N is a perfect square }

5. Number of ways in which a composite number N can be resolved into two factors which are relatively prime (or co prime) to each other is 2n1 where n is the number of different prime factors is N.

Multinomial Theorem:

Coefficient of xr in (1x)n=n+r1Cr. Number of ways of making a selection from m+n+p=N things where p are alike of one kind, m alike of second kind and n alike of third kind taken r at a time is given by coefficient of xr is expansion of (1+x+x2+ xm)(1+x+x2+ xn)(1+x+x2+..xp)

Example: Number of selection of 4 letter words from the letters for the ward PROPROTION is

{PP,RR,OOO,T,I,N}

Coefficient of x4 is (1+x+x2)(1+x+x2)(1+x+x2+x3)(1+x)(1+x)(1+x)

Condition for divisibility of a number

A number abcde will be divisible

1. by 4 if 2 d+e is divisible by 4

2. by 8 if 4c+2 d+e is divisible by 8

3. by 3 if a+b+c+d+e is divisible by 3

4. by 9 if a+b+c+d+e is divisible by 9

5. by 5 if e=0 or 5

6. by 11 if a+c+e Sum of tigits  at odd places b+d sut of didit  at ven places  is divisible by 11

7. by 6 if e= even and a+b+c+d+e is divisible by 3

8. by 18 if e= even and a+b+c+d+e is divisible by 9

Solved examples

1. The number of divisors of (6!)3! is

(a). 364

(b). 9100

(c). 2275

(d). 75

Show Answer

Solution: (6!)3!=(243251)6

=22431256

no. of divisors =25×13×7=2275

Answer: c

2. The number of ways in which three district number in AP can be selected from 1,2,3,24 is

(a). 132

(b). 572

(c). 264

(d). 150

Show Answer

Solution:

12C2+12C2=12112.12=132 (First and last number should either be both even or both odd and the middle number is average of the two)

Answer: a

3. If x,y,z are integers and x0,y1,z2 and x+y+z=15, then the number of ordered triplets (x,y,z) is

(a). 91

(b). 455

(c). 17C2

(d). none of these

Show Answer

Solution: x0,y1,z2 and x+y+z=15 Put y1=Y,z2=z1,x+y+z=12. so, we can say 12 objects ( alike) are to be distriuted among 3 persons. (distribution of alike objects)

Apply n+r1Cr1 when n=12,r=3

12+31C31=14C2=14×132=91

Answer: a

4. a,b,c,d are odd natural numbers such that a+b+c+d=20, then number of quadrapulets (a,b,c,d) is

(a). 165

(b). 455

(c). 310

(d). 255

Show Answer

Solution: Let a=2p+1, b=2q+1,c=2r+1, d=2 s+1

p+q+r+s=8

8+41C41=11C3=165 (distribution of alike objects)

Answer: a

5. The number of positive integral solutions of x+y+z10 is

Show Answer

Solution: Let x+y+z+a=10

(where x1,y1,Z1,az&a0 )

Required number =n+r1Cr1

=7+41C41=10C3

=10.9.81.2.3=120

Practice questions

1. Number of divisors of the form (4n+2);(n0) of the integer 240 is

(a). 4

(b). 8

(c). 10

(d). 13

Show Answer Answer: (a)

2. If r,s,t are prime numbers and p,q are the positive integers such that LCM of p,q is r2 s4t2, then the number of ordered pairs (p,q) is

(a). 252

(b). 254

(c). 225

(d). 224

Show Answer Answer: (c)

3. The number of seven digit integers, with sum of the digits equal to 10 and formed by using the digits 1,2 and 3 only, is

(a). 55

(b). 66

(c). 77

(d). 88

Show Answer Answer: (c)

4. Let n and k be positive integers such that nk+1C2. The number of solutions (x1,x2,.xk); x11x22,.xkk all integers satisfying x1+x2++xk=n is

(a). nk2Ck

(b). n1k2Ck

(c). n1k2Ck1

(d). n+1k2Ck1

Show Answer Answer: (c)

5. The number of divisors of the form 4n+1,n0 of the number 101011111313 is

(a). 750

(b). 840

(c). 924

(d). 1024

Show Answer Answer: (c)

6. The number of positive integer solution of the equation [x99]=[x101] is

(a). 2500

(b). 2499

(c). 1729

(d). 1440

Show Answer Answer: (b)

7. Let N be natural number. If its first digit (form the left) is deleted, it gets reduced to IV57. The sum of all the digits of N is

(a). 15

(b). 18

(c). 24

(d). 30

Show Answer Answer: (a)

8. The number of positive integral pairs (x,y) such that 1x+1y=12007,x<y is

(a). 5

(b). 6

(c). 7

(d). 8

Show Answer Answer: (c)

9. The number of ordered triplets of positive integers which satisfy the inequality 15x+y+z45 is

(a). 45C214C2

(b). 45C314C3

(c). 46C315C3

(d). none of these

Show Answer Answer: (b)

10. Match the following:

Column I Column II
(a). Total number of functions {1,2,3,4,5} {1,2,3,4,5} that are into and f(i)i is p. divisible by 11
(b). If x,x2x3=2.5.72 then the number of solution sets for (x1,x2,x3) wherexiN,xi>1 is  q. divisible by 7
(c). Number of factors of 3780 are divisible by either 3 or 2 or both is r. divisible by 3
(d). Total number of divisors of n=25.34510 that are of the form 4λ+2,λ1 is s. divisible by 4
Show Answer Answer: a\rarr p, s; b \rarr q, r; c \rarr p, s; d \rarr r

11. Read the passage and answer the following questions

Five balls are to be placed in 3 boxes. Each can hold all the five balls. In how many ways can we place the balls so that no box remains empty, when

i. Balls and boxes are all different

(a). 150

(b). 6

(c). 50

(d). 2

Show Answer Answer: (a)

ii. balls are identical but boxes are different

(a). 150

(b). 6

(c). 50

(d). 2

Show Answer Answer: (b)

iii. balls are different but boxes are identical

(a). 150

(b). 6

(c). 50

(d). 2

Show Answer Answer: (c)

iv. balls as well as boxes are identical.

(a). 150

(b). 6

(c). 50

(d). 2

Show Answer Answer: (d)