PARABOLA-8

Chord of Contact

Let PA and PB be tangents drawn through the point P(h,k).

Equation of tangent at A is

yy1=2a(x+x1)

Equation of tangent at B is

yy2=2a(x+x2)

Both lines pass through (h,k)

ky1=2a(h+x1).(1)ky2=2a(h+x2).(2)

Hence A(x1,y1) and B(x2,y2) lie on ky=2a(x+h) or T=0 ie. equation of chord AB.

Equation of chord whose midpoint (x1,y1) is given :

Sy24axS1y124axTy12a(x+x1)

Equation of AB is T=S

Reflection Property of Parabola

Module - 7

Let PQ be tangent of the parabola y2=ax at point P(at2,2at) Equation of tangent at P is ty=x+at2

Q is the point of intersection of tangent and x-axis

So Q(at2,0)

SQ=SA+AQ=a+at2=a(1+t2)

SP=PM=at2+a=a(1+t2)

SP=SQ

SPQ=SQP

Also, MPQ=PQS (alternate angles)

Hence MPQ=QPS

Also IPN=NPS

So PN normal bisects IPS

Therefore PI is incident ray then PS is reflected ray. So any ray incident parallel to axis of the parabola after reflection it passes through focus.

Examples

1. If three normals can be drawn to the parabola y22y=4x9 from the point (a,b), then the range of the value of a is

(a). (2,)

(b). (1,)

(c). (,2)

(d). (4,)

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Solution: y22y=4x9

(y1)2=4(x2)

For real three normal’s

as h>2a

a>4

Answer: d

2. A circle and a parabola y2=4ax intersect at four points. The algebraic sum of the ordinates of the four points is

(a). 0

(b). 1

(c). 1

(d). 4

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Solution: Let equation of circle be x2+y2+2gx+2fy+C=0

and equation of parabola is x=at2,y=2at

Solving it, we get

a2t4+4a2t2+2agt2+4aft+c=0a2t4+2a(2a+g)t2+4aft+c=0t1+t2+t3+t4=02a1+2a2+2a3+2a4=0y1+y2+y3+y4=0

 Or 2at1+2at2+2at3+2at4=0

Answer: a

3. Maximum number of common normals of y2=4ax and x2=4 by is

(a). 3

(b). 4

(c). 6

(d). 5

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Solution: Normals of y2=4ax and x2=4 by in slope form are

y=mx2amam2

y=mx+2b+bm2

For common normal 2b+bm2=2ama2

am4+2am3+2bm2+b=0

This mean there can be atmost 4 common normals

Answer: b

4. The curve described parametrically by x=t2+t+1,y=t2t+1 represents

(a). a pair of straight lines

(b). an ellipse

(c). a parabola

(d). a hyperbola

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Solution: x+y=2(t2+1) and xy=2t

x+y2=xy22+1

x2+y22xy+4=2x+2y

x2+y22xy2x2y+4=0

Δ=|111111114|=352=40

h2ab=11=0 It is a parabola

Answer: c

5. If x+y=k is normal to y2=12x, then k is

(a). 3

(b). 9

(c). 9

(d). 3

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Solution: Normal to y2=12x is

m=1y=x+6+3x+y=9

Answer: b

6. The equation of the common tangent touching the circle (x3)2+y2=9 and the parabola y2=4x above the x-axis is

(a). 3y=3x+1

(b). 3y=(x+3)

(c). 3y=x+3

(d). 3y=(3x+1)

Show Answer

Solution: Equation of tangent to the parabola is y=mx+1 m and equation of tangent to the circle is y=m(x3)±31+m2 both the equation are identical i.e. 1m=3m±31+m2

1m+3m2=32(1+m2)1m2+9m2+6=9+9m21=3m2m=±13

Equation of common tangent is 3y=x+3 (tangent lying above x-axis)

Answer: c