PARABOLA-6

Equation of Normal

(i) Point form :

y2=4ax

Differentiate w.r.t.x

2ydydx=4adydx=2ay

Slope of normal =y12a

Equation of normas at (x1,y1) is

yy1=y12a(xx1)

(ii) Parametric form :

P(at2,2at)

replace x1 by at2 and y1 by 2 at

y2at=2at2a(xat2)y=tx+at3+2attx+yat32at=0

(iii) Slope form:

 Replace t by my=mx2ama3

y=mx+c is normal to parabola y2=4ax if

c=2amam3 ie., condition of normal.

Equation of Normal

Parabola Point form Pt.of contact Parametric form Point of contact slope Form Pt.of contact
y2=4ax yy1=y12a(xx1) (x1,y1) y=tx+2at+at3 (at2,2at) y=mx2amam3 (am2,2am)
y2=4ax yy1=y12a(xx1) (x1,y1) y=tx+2at+at3 (at2,2at) y=mx+2am+am3 (am2,2am)
x2=4ay xx1=x12a(yy1) (x1,y1) x=ty+2at+at3 (2at,at2) y=mx+2a+am2 (2am,am2)
x2=4ay xx1=x12a(yy1) (x1,y1) x=ty+2at+at3 (2at,at2) y=mx2aam2 (2am,am2)

Equation of normal to the parabola (yk)2=4(xh) is

yk=m(xh)2amam3

Properties of Normal

1. If the normal at the point P(at112,2at1) meets the parabola at

Q(at22,2at2), then t2=t12t1

Let equation of parabola be y2=4ax.

Equation of normal at P is

y=t1x+2at1+at13

Point Q lies on the normal, so

2at2=at1t22+2at1+at132a(t2t1)=at1(t22t12)2=t1(t2+t1)t2=t12t1

2. If the normal at the points (at12,2at1) and (at22,2at2) meet on the parabola y2=4ax, then t1t2=2.

Let the equation of normal at (at12,2at1) and (at222,2at2) be

y=t1x+2at1+at13

and y=t2x+2at2+at23

meet the parabola y2=4ax at (at32,2at3) then

t3=t12t1 and t3=t22t2t12t1=t22t2t2t1=2(1t11t2)t2t1=2(t2t1t1t2)t1t2=2

3. No normal other than axis passes through focus.

Let equation of normal be y=mx2amam3

passes through (a,0) ie. focus

0=ma2ama30=ama30=am((1+m2)m=0 i.e. axis 1+m2=0 which is not possible. 

Example: 1 Three normals to y2=4x pass through the point (15,12). One of the normals is

(a) x+y=27

(b) x+4y=63

(c) 3xy=33

(d) y+3x=51

Show Answer

Solution:

Let equation of normal be y=mx2amam3. a=1

y=mx2 mm3

passes through (15,12)

12=15 m2 mm3

m313 m+12=0( m1)(m3)(m+4)=0 m=1,3,4 m=1y=x3 m=3y=3x33 m=4y+4x=72

Answer: (c)

Example: 2 The minimum distance between the curves x2+y212x+31=0 and y2=4x is

(a) 5

(b) 25

(c) 65

(d) None of these.

Show Answer

Solution:

Centre (6,0) radius =36+031=5

Minimum distance obtained along the common normal.

y2=4x

Differentiate w.r.t.x

2ydydx=4

dydx=2y

slope of normal at (x1,y1) is y12

Also slope of CQ =y10x16=y12

Points are (0,0),(4,4),(4,4)

y1=0 or x1=4

OC=6

QC=25

RC=25

Minimum distance {OCR=65QCR=255=5RCR=255=5} is 5

Answer: (a)

Important Properties :

  • If the tangent and normal at any point ’ P ’ of the parabola intersect the axis at T and N then ST =SN=SP where S in the focus.
  • The portion of a tangent to a parabola cut off between the directrix & the curve subtends a right angle at the focus.

PSQ=90

  • Any tangent to a parabola and the perpendicular on it from the focus meet on the tangent at the vertex.

PQS=90

  • If the tangents at A and B meet in P then PA and PB subtends equal angles at the focus S. (SP)2=SA×SB

SAPSPB

PSA=PSB.

  • The area of the triangle formed by three points on a parabola is twice the area of the triangle formed by the tangents at these points.

Practice questions

1. The normal at the point (2,4) of the parabola y2=8x meets the parabola at the point

(a). (18,12)

(b). (12,18)

(c). (12,18)

(d). (18,12)

Show Answer Answer: (a)

2. If y+b=m1(x+a) and y+b=m2(x+a) are two tangents to the parabola y2=4ax, then

(a). m1 m2=1

(b). m1 m2=1

(c). m1+m2=0

(d). m1m2=0

Show Answer Answer: (b)

3. If normals at the ends of the double ordinate x=4 of parabola y2=4x meet the curve again in P and P respectively, then P=

(a). 10

(b). 6

(c). 12

(d). 18

Show Answer Answer: (c)

4. Radius of the largest circle which passes through the focus of the parabola y2=4x and contained in it, is

(a). 2

(b). 4

(c). 6

(d). 8

Show Answer Answer: (b)

5. If the normal at (1,2) on the parabola y2=4x meets the parabola again at the point (t2,2t), then t is

(a). 3

(b). 1

(c). 2

(d). 3

Show Answer Answer: (d)

6. If x=my+c is a normal to the parabola x2a4+aam Then c=

(a). 2am+a3

(b).

(c). 2amam3

(d). 2amam3

Show Answer Answer: (c)