PARABOLA-4

Line and Parabola:

Let equation of line be y=mx+c and equation of parabola be y2=4ax.

(mx+c)2=4ax

m2x2+2x(mc2a)+c2=0

D={2(mc2a)}24m2c2

=4(4a24amc)

If D<0, line do not intersect parabol(a).

i.e. a<mc

If D=0 i.e. a=mc, line touches the parabola (condition of tangency)

If D>0 i.e. a>mc, line intersect the parabola at two points.

Equation of tangent (Point form)

Equation of parabola y2=4ax

Differentiate w.r.t.x

2ydydx=4a

slope of tangent =2ay1

Equation of tangent yy1=2ay1(xx1)

y1y12=2ax2ax1y1=2ax+2ax1y1=2a(x+x1)

Equation of tangent (Paramatric form)

y2at=2a(x+at2)ty=x+at2

Equation of tangent (slope form)

y=mx+am

Point of contact am2,2am

  • Equation of tangent to the parabola (yk)2=4a(xh) is

yk=m(xh)+am

Equation of tangent:

Parabola Point form Pt. of contact Parametric form Pt. of contact slope form Pt. of contact
y2=4ax yy1=2a(x+x1) (x1,y1) ty=x+at2 (at2,2at) y=mx+am am2,2am
y2=4ax yy1=2a(x+x1) (x1,y1) ty=x+at2 (at2,2at) y=mxam am2,2am
x2=4ay xx1=2a(y+y1) (x1,y1) tx=y+at2 (2at,at2) x=my+am 2am,am2
x2=4ay xx1=2a(y+y1) (x1,y1) tx=y+at2 (2at,at2) x=myam 2am,am2

Pair of Tangents from point (x1,y1)

Let eq of parabola be y2=4ax

Sy24ax

S1y124ax1

Tyy12a(x+x1)

Equation of pair of tangents is SS1=T2 i.e.

(y24ax)(y124a1)={y12a(x+x1)}2

Properties of Tangents:

1. Point of intersection of two tangents of the parabola:-

Equation of tangent at P is t1y=x+at12

Equation of tangent at Q is t2y=x+at22

Solving these equations, we get

x=at1t2,y=at1+at2

A(at1t2,a(t1+t2))

2. Locus of foot of prependicular from focus upon any tangent is tangent at vertex:-

Equation of tangent at P is ty =x+at2

Let the tangent meet y-axis at Q then Q(0, at

 slope of QS=ata=t slope of tangent =1t1t×(t)=1SQ tangent 

3. Length of tangent between the pt. of contact and the point where tangent meets the directrix subtends right angle at focus:-

Eqation of tangent at P(t)

ty=x+at2

Point of intersection with directrix x=a is

a,atat

slope SP=2atat2a=2tt21

 slope QS=atat2a=t212tm1m2=1PSQS

4. Tangent at extremities of focal chord are perpendicular and intersect on directrix

(Locus of intersection point of tangents at extremities of focal chord is directrix)

Let P(att2, 2at) and Qat2,2at

Equation of tangent at Pty=x+at2..(1)

Equation of tangent at Q1ty=x+at2

y=txat.(2)

Point of intersection of both tangents, we get after sloving (1) & (2) i.e.

x+a=0

A point lies on the directrix.

Practice questions

1. If the tangents to the parabola y2=4ax at the points (x1,y1) and (x2,y2) meet at the point (x3,y3) then

(a). y32=y1y2

(b). 2y3=y1+y2

(c).

(d). none of these

Show Answer Answer: (a)

2. A right angled triangle ABC is inscribed in parabola y2=4x, where A is vertex of parabola and BAC=90. If AB=, then area of ABC is

(a). 40

(b). 10

(c). 20

(d). 45

Show Answer Answer: (c)

3. The locus of the point (3h,3k+2) if it lies on the line xy1=0 is a

(a). circle

(b). parabola

(c). straight line

(d). none of these

Show Answer Answer: (b)

4. The length of the chord of the parabola y2=x which is bisected at the point (2,1) is

(a). 5

(b). 4

(c). 25

(d). 52

Show Answer Answer: (c)

5. If y=mx+c touches the parabola y2=4a(x+a), then

(a). c=am

(b). c=a+am

(c). c=2am

(d). c=am+am

25y3=1y1+1y2

Show Answer Answer: (d)