ELLIPSE-3

Topics covered

1. Auxilliary circle

2. Eccentric angle

3. Equation of chord

4. Position of a point with respect to an ellipse.

1. Auxiliary Circle

The circle described on the major axis of an ellipse as diameter is called an auxiliary circle of the ellipse

If x2a2+y2b2=1 is an ellipse then its auxiliary circle is x2+y2=a2

2. Eccentric angle of a point

Let P be any point on the ellipse x2a2+y2 b2=1

Draw PM perpendicular to major axis from P and produce MP to meet the auxiliary circle at Q. Join CQ. QCA=θ is called eccentric angle of point P Note that the angle ACP is not eccentric angle. i.e. eccentric angle of P on an ellipse is the angle which the radius through the corresponding point on, the auxiliary circle makes with the major axis

Q(acosθ,asinθ)

x-coordinate of P is acos θ

a2cos2θa2+y2 b2=1

y2 b2=1cos2θ

y2=b2sin2θ

y=bsinθ

Coordinate of P is (acosθ,bsinθ)

i.e. x=acosθ and y=bsinθ is the parameter equations of the ellipse.

(acosθ,bsinθ) is also called the point ’ θ '

3. Equation of the chord

LetP(acosθ,bsinθ) and Q(acosϕ,bsinϕ) be any two points of the ellipse x2a2+y2 b2=1 then the equation of the chord joining these two points is

ybsinθ=bsinϕbsinθacosϕacosθ(xacosθ)

Simplifying the equation we get

xacos(θ+ϕ2)+ybsin(θ+ϕ2)=cosθϕ2

θ&ϕ are eccentric angle of points P and Q of ellipse

4. Position of a point (h,k) with respect to an ellipse

Let ellipse be x2a2+y2b2=1

Now P will lie outside, on or inside the ellipse x2a2+y2 b2=1 according as

h2a2+k2 b21>,=,<0

Examples

1. Find the equation of the curve whose parametric equation are x=1+4cosθ,y=2+3sinθR

Show Answer

Solution: We have x=1+4cosθ,y=2+3sinθ

x14=cosθ and y23=sinθ

Squaring and adding we get

(x14)2+(y23)2=cos2θ+sin2θ(x1)216+(y2)29=1

Which is an ellipse.

2. Find the eccentric angle of a point on the ellipse x26+y22=1 whose distance from the centre of the ellipse is 5

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Solution :

We have x26+y22=1

a2=6b2=2a=6b=2

any point on the ellipse with θ as eccentric angle is P(6cosθ,2sinθ)

Here centre is origin

CP=6cos2θ+2sin2θ=56cos2θ+2sin2θ=54cos2θ=3cos2θ=34cosθ=±32θ=π6,5π6,7π6,11π6

3. If α and β are the eccentric angles of the extremities of a focal chord of an ellipse, then the eccentricity of the ellipse is

(a) cosα+cosβcos(αβ)

(b) sinαsinβsin(αβ)

(c) cosαcosβcos(αβ)

(d) sinα+sinβsin(α+β)

Show Answer

Solution : Equation of chord joining points having eccentric angles α and β is

xacos(α+β2)+ybsin(α+β2)=cos(αβ2)

Since these points are extremities of focal chord so it passes through focus (ae, 0 ) then

ecos(α+β2)=cos(αβ2)

e=cos(αβ2)cos(α+β2)

Multiply & divide by 2sin(α+β2) on right side

e=2sin(α+β2)cos(αβ2)2sin(α+β2)cos(α+β2)

e=sinα+sinβsin(α+β)

4. An ellipse passes through the point (4,1) and touches the line x+4y10=0. Find its equation of its axes coincide with coordinate axes.

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Solution : Let the equation of ellipse be x2a2+y2b2=1

It passes through (4,1)

16a2+1 b2=1 or a2+16 b2=a2 b2(1)

x+4y10=0 is a tangent to the ellipse.

y=14x+104y=mx+c

m=14,c=104

c=a2m2+b2 is a condition for tangent

104=a2×116+b2

10016=a216+b2

16b2=100a2

a2+16b2=100

From (1) we get

100=a2 b2

b2=100a2

a2+1600a2=100

a4100a2+1600=0

a480a220a2+1600=0

a2(a280)20(a280)=0

(a280)(a220)=0

b2=108=54 or b210020=5

Equation of ellipse is x280+4y25=1

 or x220+y25=1

5. If xa+yb=2 touches the ellipse x2a2+y2b2=1, then find its eccentric angle θ of point of contact.

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Solution : Let θ be the eccentric angle of the point of contact :

coordinates of the point is (acosθ,bsinθ)

Equation of tangent at this point is

xcosθa+ysinθb1=0.(1)

Given that xa+yb2=0(2) is tangent

Comparing (1) and (2) as these two are identical, we get

cosθaa=sinθbb=12cosθ=12=sinθθ=π4

Practice questions

1. The sum of the squares of the reciprocals of two perpendicular diameter of an ellipse is

(a) 14(1a2+1 b2)

(b) 12(1a2+1 b2)

(c) 1a2+1 b2

(d) None of these

Show Answer Answer: (a)

2. Prove that any point on the ellipse whose foci are (1,0) and (7,0) and eccentcicity 12 is (3+8cosθ,43sinθ),θR. Also find the eq of the ellipse

Show Answer Answer: (x3)264+y248=1

3. Let E be the ellipse x29+y24=1 and C be the circle x2+y2=9. Let P and Q be the points

(1,2) and (2,1) respectively. Then

(a) Q lies inside C but outside E

(b) Q lies outside both C and E

(c) P lies inside both C and E

(d) P lies inside C but outside E

Show Answer Answer: (d)

4. P is a variable on the ellipse x2a2+y2 b2=1 with AA as the major axis. Then the maximum area of the triangle APA is

(a) ab

(b) 2ab

(c) ab/2

(d) None of these

Show Answer Answer: (a)

5. A man running round a race course notes that the sum of the distances of two flag-posts from him is always 10 m and the distance between the flag-posts is 8 m. The area of the path he encloses in square meters is

(a) 15π

(b) 12π

(c) 18π

(d) 8π

Show Answer Answer: (a)

6. If the line x+my+n=0 cuts the ellipse x2a2+y225=1 in points whose eccentric angles differ by π2 then a22+b2 m2n2

(a) 1

(b) 2

(c) 4

(d) 3/2

Show Answer Answer: (b)

7. If PSQ is a focal chord if the ellipse 16x2+25y2=400 such that SP=8, then SQ=

(a) 1

(b) 2

(c) 3

(d) 4

Show Answer Answer: (b)

8. If equation of the ellipse is 2x2+3y28x+6y+5=0 then which of the following are true?

(a) equation of director circle is x2+y24x+2y=10

(b) director circle will pass through (4,1)

(c) equation of auxillary circle is x2+y24x+2y+2=0

(d) None of these

Show Answer Answer: (c)

9. The foci of ellipse (x5)2+(y3)2=1 are S and S. P is a point on ellipse whose eccentric angle is π/3. The incentre of triangle SPS is

(a) (2,3)

(b) (2,23)

(c) (2,32)

(d) (3,2)

Show Answer Answer: (b)