ELLIPSE-2

Examples

1. The equation x210a+y24a=1 represents an ellipse if

(a) a<4

(b) a>4

(c) 4<a<10

(d) a>10

Show Answer

Solution : Here equation of ellipse is

x210a+y24a=1

a2=10a and b2=4a

10a>0 and 4a>0

10>a and 4>a

a<4.

2. The radius of the circle passing through the foci of the ellipse x216+y29=1 and having its centre (0,3) is

(a) 4

(b) 3

(c) 12

(d) 7/2

Show Answer

Solution :

x216+y29=1a2=16b2=9a=4b=3a>be=1b2a2=1916=716=74

Foci =(±ae,0) foci is (±7,0)

Radius of the circle through foci & centre (0,3) is (7)2+32=7+9=16=4.

3. The equation of the ellipse whose focus is (1,1) directrix xy3=0 and eccentricity 12 is

(a) 7x2+2xy+7y210x+10y+7=0

(c) 7x2+2xy+7y2+10x10y7=0

(b) 7x2+2xy+7y2+7=0

(d) None of these

Show Answer

Solution : Let P(xy) be any point on the ellipse

Then by definition SP=ePM.

(x1)2+(y+1)2=12|xy32|

(x1)2+(y+1)2=18(x2+y2+92xy+6y6x)

8x216x+8+8y2+16y+8=x2+y22xy+6y6x+9

7x2+7y2+2xy10x+10y+7=0

4. The equation (5x1)2+(5y2)2=(λ22λ+1)(3x+4y1)2 represents an ellipse if λ.

(a) (0,1)

(b) (0,2){1}

(c) (1,2)

(d) (1,0)

Show Answer

Solution :

(5x1)2+(5y2)2=(λ2λ+1)(3x+4y1)2

25(x15)2+25(y25)2=(λ1)2(3x+4y1)2

(x15)2+(y25)2=(λ1)2(3x+4y1)225

Sp2=e2(PM)2

e=|λ1|

In ellipse 0<e<1

0<|λ1|<10<λ<2{1}λ(0,2){1}

5. The eccentricity of an ellipse x2a2+y2b2=1 whose latus rectum is half of its major axis is

(a) 12

(b) 23

(c) 32

(d) None of these

Show Answer

Solution:

x2a2+y2 b2=1a>b major axis =2a latus rectum is =2 b2a=a

 According to question ;2b2a=a2b2=a2 eccentricity e =1b2a2=112=12

6. If (5,12) and (24,7) are the foci of an ellipse passing through the origin, then the eccentricity of the conic is

(a) 38612

(b) 38613

(c) 38625

(d) 38638

Show Answer

Solution :

S(5,12),S(24,7)

SP=52+122=13SP=242+72=25 S=2ae=192+52=361+25=386=3862aeSP+SP=2a=13+252a=38a=19e=SSSP+SP=2ae2a=38638

7. Locus of the point which divides double ordinate of the ellipse x2a2+y2b2=1 in the ratio 1:2 internally is

(a) x2a2+9y2b2=1

(b) x2a2+9y2 b2=19

(c) 9x2a2+9y2b2=1

(d) None of these.

Show Answer

Solution :

Let P(h,k) be a point divides double ordinate in the ratio 1:2 internally

Let coordinates of ends of double ordinate (h,y1) and (h,y1).

By section formula k=y1+2y13=y13

y1=3k

Now the point (h,y1)=(h,3k) lies on the ellipse

h2a2+9k2 b2=1 or x2a2+9y2 b2=1((h,k) are arbitrary )

8. If C is the centre of the ellipse 9x2+16y2=144 and S is one focus. The ratio of CS to semi major axis is

(a) 7:16

(b) 7:4

(c) 5:7

(d) None of these

Show Answer

Solution : Here equation of ellipse is

9x2+16y2=144

x216+y29=1

16>9a>b

e=1b2a2

=1916

=716

e=74

Foci is (±ae,0)=(±7,0)

Semi major axis is =2a2=a=4

CS=7 and semi major axis is 4.

Required ratio is 7:4.

Practice questions

1. The equation of the circle drawn with the two foci of x2a2+y2b2=1 as the end points of a diameter is

(a) x2+y2=a2+b2

(b) x2+y2=a2

(c) x2+y2=2a2

(d) x2+y2=a2b2

Show Answer Answer: (d)

2. The radius of the circle passing through the foci of the ellipse x216+y27=1 and having its centre (0,3) is

(a) 32

(b) 3

(c) 12

(d) 72

Show Answer Answer: (a)

3. x2r2r6+y2r26r+5=1 will represents the ellipse, if r lies in the interval

(a) (,2)

(b) (3,)

(c) (5,)

(d) (1,)

Show Answer Answer: (c)

4. The semi latus rectum of an ellipse is

(a) The AM of the segments of its focal chord.

(b) The GM of the segments of its focal chord

(c) The HM of the segments of its focal chord

(d) None of these

Show Answer Answer: (c)

5. The following equation represents an ellipse 25(x26x+9)+16y2=400. How should the axes be transformed so that the ellipse is represented by the equation x216+y225=1______

Show Answer Answer: (3, 0)

6. Let P be a variable point on the ellipse x216+y225=1 with foci S1 and S2. It A be area of the triangle PS1 S2 then the maximum value of A is ________

Show Answer Answer: (12)

7. In an ellipse, if the lines joining a focus to the extremities of the minor axis make an equilateral triangle with the minor axis, the eccentricity of the ellipse is

(a) 3/4

(b) 3/2

(c) 1/2

(d) 2/3

Show Answer Answer: (b)

8. Column Matching:

For the ellipse x25+y24=1

Column I Column II
1. x=0 a. a directrix
2. y=0 b. a latus rectum
3. x=1 c. minor axis
4. x=5 d. major axis
Show Answer Answer: 1 \rarr c; 2 \rarr d; 3 \rarr b; 4 \rarr a

9. The centre of the ellipse 14x24xy+11y244x58y+71=0 is..

Show Answer Answer: (3, 1)


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