COMPLEX NUMBERS AND QUADRATIC EQUATIONS - 4 (Quadratic Equations)

Problem solving skills.

  • If one root of ax2+bx+c=0 is n times the other, then (n+1)2ac=nb2

  • If one root of ax2+bx+c=0 is square of the other, then (a2c)1/3+(ac2)1/3+b=0

  • If α,β are roots of ax2+bx+c=0 then

(i) α,β are roots of ax2bx+c=0

(ii) 1α,1β are roots of cx2+bx+a=0;ac0

(iii) kα,kβ are roots of ax2+kbx+k2c=0

(iv) α2,β2 are roots of a2x2(b22ac)x+c2=0

  • If the sum of the coefficient of f(x)=0 is 0 , then 1 is always a root of f(x)=0. Also x1 is a facter of f(x).

In particular, for ax2+bx+c=0 if

a+b+c=0, then 1 is always a root and the other root=ca( product of roots =ca).

  • f(x)=(xa1)2+(xa2)2+..+(xan)2, where aiRi.

f(x) assumes its least value when x=a1+a2++ann

  • While solving an equation, if you have to square, then additional roots will occur as the degree of the equation will change. In such cases, you have to check whether the roots satisfy the original equation or not.

Solved examples

1. If α,β are roots of the equation x22x+3=0

Then the equation whose roots are

α33α2+5α2 and β3β2+β+5 is

(a) x2+3x+2=0

(b) x23x2=0

(c) x23x+2=0

(d) None

Show Answer

Solutions :

α22α+3=0 and β22β+3=0

α3=2α23α and β3=2β23β

P=α33α2+5α2=2α23α3α2+5α2=α2+2α2

=32=1

Similarly, we can show that Q=β3β2+β+5=2

Sum =1+2=3 and product =1×2=2

Hence x23x+2=0

Answer: (c)

2. If α,β are roots of the equatio x2+px12p2=0,pR{0}, then the minimum value of α4+β4 is

(a) 22

(b) 22

(c) 2

(d) 2+2

Show Answer

Solutions :

α4+β4=(α2+β2)22α2β2=((α+β)22αβ)22(αβ)2

=(p2+1p2)212p4=p4+12p4+2

=(p212p2)2+2+2

Min value is 2+2.

Answer: (d)

3. Let p(x) be a polynomial of least possible degree with rational coefficients, having 713+4913 as one of its roots, then the product of all roots of p(x)=0 is

(a) 56

(b) 63

(c) 7

(d) 49

Show Answer

Solutions :

Let x=713+4913

Cubing x3=(713)3+(4913)3+3.7134913(713+4913)

x3=7+49+3.7(713+4923)

x3=56+21x

x3+0x221x56=0

Product of roots is 56

Answer: (a)

4. If α,β,γ,δ are roots of x4+4x36x2+7x9=0, then the value of (1+α2)(1+β2)(1+γ2)(1+δ2) is

(a) 9

(b) 11

(c) 13

(d) 5

Show Answer

Solution :

x4+4x36x2+7x9=(xα)(xβ)(xγ)(xδ) Put x=i,i4+4i36i2+7i9=(iα)(iβ)(iγ)(iδ)2+3i=(iα)(iβ)(iγ)(iδ)(1)Putx=i23i=(iα)(iβ)(iγ)(iδ).(2)

Multiply (1) & (2)

49i2=(α2i2)(β2i2)(γ2i2)(δ2i2)

13=(1+α2)(1+β2)(1+γ2)(1+δ2)

Answer: (c)

5. If α,β,γ, are roots of 8x3+1001x+2008=0, then the value of (α+β)3+(β+γ)3+(γ+α)3 is

(a) 251

(b) 751

(c) 735

(d) 753

Show Answer

Solution :

α+β+γ=0

(α+β)3+(β+α)3+(γ+α)3=(γ)3+(α)3+(β)3

=3αβγ=3(20088)=753

Answer: (d)

6. Total number of integral values of ’ n ’ so that the equation x2+2xn=0(nN) and n[5,100] has integral roots is

(a) 2

(b) 4

(c) 6

(d) 8 and n[5,100]

Show Answer

Solution :

x2+2xn=0

x2+2x+1=n+1

(x+1)2=n+1

x+1=±n+1n+1 should be perfect square

n[5,100]

n+1[6,101]

Perfect squares in the given interval are

9,16,25,36,49,64,81,100

8 values

Answer: (d)

7. If the equation p(qr)x2+q(rp)x+r(pq)=0 has equal roots, then 2q is equal to

(a) 1p+1r

(b) p+r

(c) 1p+r

(d) p+1r

Show Answer

Solution :

Clearly x=1 is one root and the other root is r(pq)p(qr) roots are equal, we have

r(pq)p(qr)=1( Product of roots =r(pq)p(qr))rprq=pqrq2rp=pq+rq

2q=1p+2r

Answer: (a)

Practice questions

1. The largest interval for which x12x9+x4x+1>0 is

(a) 4<x0

(b) 0<x<1

(c) 100<x<100

(d) <x<

Show Answer Answer: (d)

2. Read the following passage and answer the questions.

If a continuous function f defined on the real line R, assumes positive and negative values in R, then the equation f(x)=0 has a root in R, for example, if it is known that a continous function f on R is positive at some point and its minimum value is negative, then the equations f(x)=0 has a root in R. Consider f(x)=kexx,xR where kR is a constant.

(i) The line y=x meets y=kex for k0 at

(a) no point

(b) one point

(c) two point

(d) more than two points

Show Answer Answer: (b)

(ii) The value of k for which kexx=0 has only one root is

(a) 1e

(b) e

(c) loge2

(d) 1

Show Answer Answer: (a)

(iii) For k>0, the set of all values of k for which kexx=0 has two distinct roots is

(a) (0,1e)

(b) (1e,1)

(c) (1e,)

(d) (0,1)

Show Answer Answer: (a)

3. If 2615352(38+53)=a2, then a is

(a) 13

(b) 13

(c) 3

(d) None of these

Show Answer Answer: (d)

4. Solution of 2logxa+logaxa+3logba=0, where a>0,b=a2x is

(a) a1/2

(b) a4/3

(c) a1/2

(d) None of these

Show Answer Answer: (a, b)

5. Solution of the system of equations

x+3xyx2+y2=3,yx+3yx2+y2=0 is .or ..

Show Answer Answer: (2,1),(+1,1)

6. The number of ordered 4-tuple (x,y,z,w) where x,y,z,w[1,10], which satisfies the inequality 2sin2x3cos2y4sin2z5cos2w120 is

(a) 0

(b) 144

(c) 81

(d) infinite.

Show Answer Answer: (c)

7. The number of solutions of the following inequality

21sin2x231sin2x341sin2x4...n1sin2xnn ! where

xi(0,2π) for i=1,2,3.n is

(a) 1

(b) 2n1

(c) nn

(d) infinite

Show Answer Answer: (b)

8. The number of solutions of |[x]2x|=4 is

(a) infinite

(b) 4

(c) 3

(d) 2

Show Answer Answer: (b)

9. How many roots does the equation 3|x||2|x||=1 possess?

(a) 1

(b) 2

(c) 3

(d) 4

Show Answer Answer: (d)

10. Let S be the set of values of ’ a ’ for which 2 lie between the roots of the quadratic equation x2+(a+2)x (a+3)=0, then S is gives by

(a) (,5)

(b) (5,)

(c) (,5]

(d) [5,)

Show Answer Answer: (a)

11. Match the following

For what values of m, the equation 2x22(m+1)x+m(m+1)=0 has (mR)

ColumnI Columan II
(a) both roots are smaller than 2 (p) {0,3}
(b) both roots are grater than 2 (q) (0,3)
(c) both roots lie in the interval (2,3) (r) (,0)(3,)
(d) exactly one root lie in the interval (2,3) (s) ϕ
(e) one root is smaller than 1 , the other root is greater than 1 (t) {81+662532,81662532}
(f) both 2&3 lie between the roots (u) (,1)[3,)
Show Answer Answer: a \rarr q; b \rarr p; c \rarr r; d \rarr v; e \rarr s; f \rarr t

12 The real roots of the equation

x+2x+2x+.+2x+23x=x is 

(n radical signs)

(a) 0

(b) 3

(c) 1

(d) None of these

Show Answer Answer: (a, b)

13. Solution of the equation 1+3x/2=2x is……

Show Answer Answer: 2

14. The number of real solutions of the system of equations

x=2z21+z2, y=2x21+x2, z=2y21+y2 is

(a) 1

(b) 2

(c) 3

(d) 4

Show Answer Answer: (a)

15. If a,b,c>0,a2=bc and a+b+c=abc, then the least value of a4+a2+7 must be equal to

(a) 19

(b) 20

(c) 21

(d) 18