COMPLEX NUMBERS AND QUADRATIC EQUATIONS - 1 (Quadratic Equations)

Quadratic equations

The general form of a quadratic equation over real numbers is ax2+bx+c=0 where a,b,cR&a 0 . The solution of the quadrati equation ax2+bx+c=0 is given by

x=b±b24ac2a. The expression b24ac is called the discriminant of the quadratic equation and is denoted by D.

Nature of roots : For the quadratic equation ax2+bx+c=0, where a,b,cR and a0, then

For the quadratic equation ax2+bx+c=0 where a,b,cQ and a0, then :

Note 1: If α is a root of f(x)=0, then the polynomial f(x) is exactly divisible by xα or (xα) is a factor of f(x) and vice versa.

Note 2: x2+bx+c=0 cannot have three different roots. If it has, then the equation becomes an identity in x. ie, a=b=c=0.

Relation between roots and coefficients

If α1,α2,αn are roots of the equation f(x)=anxn+an1xn1+an2xn2+a2x2+a1x+a0=0, then f(x)=an(xα1)(xα2)(xα3) (xαn)

anxn+an1xn1+an2xn2++a2x2+a1x+a0=an(xα1)(xα2).

Comparing the coefficients of like powers of x an both sides, we get,

S1=α1+α2++αn=αi=an1an= coeft. of xn1 coeft of xnS2=α1α2+α1α3+ijαiαj=(1)2an2an=(1)2 coeft. of xn2 coeft of xnS3=α1α2α3+α2α3α4+ijkαiαjαk=(1)3an3an=(1)3 coeft. of xn3 coeft of xn

Sn=α1α2α3αn=(1)na0an=(1)n constant term coeft of xn

Here Sk denotes the sum of the products of the roots taken ’ k ’ at a time.

Particular cases :-

Quadratic equation : If α&β are the roots of the quadratic equation ax2+bx+c=0, then S1=α+β=ba,& S2=αβ=ca

Cubic equation: If α,β,γ are the roots of the cubic equation ax3+bx2+cx+d=0, then

S1=α+β+γ=baS2=αβ+βα+γα=(1)2ca=caS3=αβγ=(1)3da=da

Biquadratic equation : If α,β,γ,δ are roots of the biquadratic equation ax4+bx3+cx2+dx+e=0, then

S1=α+β+γ+δ=ba constant term  coeft of nS2=αβ+βγ+αδ+βγ+βδ+γδ=(1)2ca Or S2=(α+β)(γ+δ)+αβ+γδ=caS3=αβγ+βγδ+γδα+αβδ=(1)3da Or S3=αβ(γ+δ)+γδ(α+β)=da and S4=αβγδ=(1)4ea=ea

Formation of a polynomial equation from given roots

If α1,α2,α3,,αn are the roots of an nth  degree equation, then the equation is xnS1xn1+S2xn2S3xn3+.+(1)nSn=0 where Sk denotes the sum of the products of roots taken k at a time.

Particular cases

Quadratic equation : If α,β are the roots of a quadratic equation, then the equation is x2S1x+S2=0 ie, x2(α+β)x+αβ=0.

Cubic equation : If α,β,γ are the roots of a cubic equation. Then the equation is, x3S1x2+S2xS3=0 ie, x3(α+β+γ)x2+(αβ+βγ+γα)xαβγ=0

Biquadratic equation : If α,β,γ,δ are the roots of a biquadratic equation, then the equation is x4S1x3+S2x2S3x+S4=0

ie, x4(α+β+γ+δ)x3+(αβ+βγ+γδ+αδ+βδ+αγ)x2 (αγβ+αβδ+βγδ+αγδ)x+αβγδ=0.

Quadratic Expression : An expression of the form ax2+bx+c, where a,b,cR&a0 is called a quadratic expression in x. So in general quadratic expression is represented as: f(x)=ax2+bx+c or y= ax2+bx+c.

Graph of a quadratic Expression

Let y=ax2+bx+c where a0.

Then y=a(x2+bax+ca)y=a(x2+bxa+b24a2+cab24a2)

y+b24ac4a=a(x+b2a)2y+D4a=a(x+b2a)2

Let y+D4a=Y&x+b2a=X

Y=aX2 or X2=Ya

Clearly it is the equation of a parabola having its vertex at (b2a,D4a).

If a>0, then the parabola open upwards.

If a<0, then the parabola open downwards.

Sign of quadratic Expression

(1) The parabola will intersect the x-axis in two distinct points if D>0.

(i) a>0

Let f(x)=0 have 2 real roots

α&β(α<β). Then f(x)>0

x(,α)(β) and f(x)<0

x(α,β)

(ii) a<0

Let f(x)=0 have 2 real roots

α&β(α<β) Then f(x)<0

x(,α)(β)

&f(x)>0 for all x(α,β)

(2) The parabola will touch the x-axis at one point if D=0

(3) The parabola will not intersect x-axis if D<0.

NOTE : Condition that a quadratic function f(x,y)=ax2+2hxy+by2+2gx+2fy+c may be resolved into two linear factions is that

abc+2fghaf2b2ch2=|ahghbfgfc|=0

NOTE :

(i) For a>0,f(x)=ax2+bx+c has least value at x=b2a. This least value is given by D4a

(ii) For a<0,f(x)=ax2+bx+c has greatest value at x=b2a. This greatest value is given by D4a

Solved Examples

1. If α,β are roots of ax2+bx+c=0;α+h and β+h are roots of px2+qx+r=0 and D1,D2 are their discriminants, then D1:D2=

(a). a2p2

(b). b2q2

(c). c2r2

(d). None of these

Show Answer

Solution : αβ=(α+h)(β+h)

(αβ)2=((α+h)(β+h))2(α+β)24αβ=((α+h)+(β+h))24(α+h)(β+h)(ba)24ca=(qp)24rp

b24aca2=q24prp2D1a2=D2p2D1D2=a2p2

Answer : (a).

2. If aZ and the equation (xa)(x10)+1=0 has integral roots, then the values of a are

(a). 10, 8

(b). 12, 10

(c). 12, 8

(d). None of these

Show Answer

Solution: (xa)(x10)=1

xa=1&x10=19a=1x=101a=8x=9

 OR xa=1&x10=111a=1x=11a=12

Answer : (c).

3. If α,β are roots of the equation (xa)(xb)+c=0(c0), then then roots of the equation ( xc α)(xcβ)=c are

(a). a and b+c

(b). a+c and b

(c). a+c and b+c

(d). None of these

Show Answer

Solution: x2(a+b)x+ab+c=0

α+β=a+b and αβ=ab+c

Now (xcα)(xcβ)=c

(xc)2(α+β)(xc)+αβc=0

(xc)2(a+b)(xc)+ab=0

(xc)2a(xc)b(xc)+ab=0

(xca)(xcb)=0

x=c+a and b+c

Answer: (c).

4. Let Δ2 be the discriminant and α,β be the roots of the equation ax2+bx+c=0. Then 2aα+Δ and 2aβΔ can be roots of the equation

(a). x2+2bx+b2=0

(b). x22bx+b2=0

(c). x2+2bx3b216ac=0

(d). x2+2bx3 b2+16ac=0

Show Answer

Solution : α,β=b±Δ22a

quadatic equation is

  • x2+2bx3 b2+16ac=0

quadratic equation is

  • x2+2bbx+b2=0

Answer : (a and d)

5. The polynomial equation (ax2+bx+c)(ax2dxc)=0,ac0 has

(a). four real roots

(b). atleast two real roots

(c). atmost two real roots

(d). No real roots

Show Answer

Solution : ac0

ac>0 or ac<0

Now D1=b24ac&D2=d2+4ac

When ac >0D2>0 but D1 may positive or negative

When ac <0D1>0 but D2 may be positive or negative In either case the polynomial has atleast two real roots

Answer: (b).

6. If α,β are roots of x2p(x+1)q=0, then the value of α2+2α+1α2+2α+q+β2+2β+1β2+2β+q is

(a). 1

(b). 2

(c). 3

(d). None of these

Show Answer

Solution : x2pxpq=0

α+β=p and αβ=pqNow(α+1)(β+1)=(α+β)+αβ+1=pqp+1=1q Now α2+2α+1α2+2α+q+β2+2β+1β2+2β+q=(α+1)2(α+1)2+q1+(β+1)2(β+1)2+q1=(α+1)2(α+1)2(α+1)(β+1)+(β+1)2(β+1)2(α+1)(β+1)=11(β+1α+1)+11(α+1)β+1=α+1(α+1)(β+1)+β+1β+1(α+1)=α+1αβ+β+βα=α+1β1αβαβαβ=1

Answer: (a).

7. Let α,β,γ be the roots of the equation x3+4x+1=0, then (α+β)1+(β+γ)1+(γ+α)1 equals

(a). 2

(b). 3

(c). 4

(d). 5

Show Answer

Solution : α+β+γ=0,αβ+βγ+γα=4,αβγ=1

1α+β+1β+γ+1γ+α=1γ1α1β=αβ+βγ+γααβγ=(41)=4

Answer : (c).

Practice questions

1. The minimum value of f(x)=x2+2bx+2c2 is greatest than the maximum value of g(x)=x22cx+b2, then ( x being a real )

(a). |c|>|b|3

(b). |c|2>|b|

(c). 1<c<2 b

(d). Non real value of b & c exist

Show Answer Answer: (b)

2. If P(x) is a polynomial of degree less than or equal to 2 and S is the set of all such polynomials so that P(1)=1,P(0)=0 and P1(x)>0x[0,1], then S= Here, P(x)=bx2+ax+c

(a). ϕ

(b). {(1a)x2+ax,0<a<2}

(c). {(1a)x2+ax,a>0}

(d). {(1a)x2+ax,0<a<1}

Show Answer Answer: (b)

3. In the quadratic equation ax2+bx+c=0 if Δ=b24ac and α+β,α2+β2 and α3+β3 are in G.P, where α,β are the roots of the equation, then

(a). Δ0

(b). bΔ=0

(c). cΔ=0

(d). Δ=0

Show Answer Answer: (c)

4. If a,b,c are the sides of a triangle ABC such that x22(a+b+c)x+3λ(ab+bc+ca)=0 has real roots, then

(a). λ<43

(b). λ>53

(c). λ(43,53)

(d). λ(13,53)

Show Answer Answer: (a)

5. Let α&β be the roots of x26x2=0, with α>β. If an=αnβn for n1, then the value of a102a82a9 is

(a). 1

(b). 2

(c). 3

(d). 4

Show Answer Answer: (c)

6. If x210ax11b=0 have roots c&dx210cx11d=0 have roots a&b, then a+b+c+d is

(a). 1210

(b). 1120

(c). 1200

(d). None of these

Show Answer Answer: (a)

7. If tn denotes the nth  term of an A.P. and tp=1q and tq=1p, then which of the following is necessarily a root of the equation (p+2q3r)x2+(q+2r3p)x+(r+2p3q)=0 is

(a). tp

(b). tq

(c). tpq

(d). tp+q

Show Answer Answer: (c)

8. The curve y=(λ+1)x2+2 intersect the curve y=λx+3 in exactly one point, if λ equals

(a). {2,2}

(b). {1}

(c). {2}

(d). {2}

Show Answer Answer: (c)

9. Read the passage and answer the following questions.

Consider the equation x4+(12k)x2+k21=0 where k is real. If x2 is imaginary, or x2<0, the equation has no real roots. If x2>0, the equation has real roots.

(i) The equation has no real roots if k

(a). (1)

(b). (1,1)

(c). (1,54)

(d). (54,)

Show Answer Answer: (a, d)

(ii) The equation has only two real roots if k

(a). (1)

(b). (0,1)

(c). (1,2)

(d). (1,1)

Show Answer Answer: (d)

(iii) The equation has four real roots if k

(a). (,0)

(b). (1,1)

(c). (1,54)

(d). (1,)

Show Answer Answer: (c)

10. If α,β are the roots of the equation ax2+bx+c=0, then the value of |1cos(βα)cosαcos(αβ)1cosβcosαcosβ1| is

(a). sin(α+β)

(b). sinαsinβ

(c). 1+cos(α+β)

(d). None of these

Show Answer Answer: (d)

11. If (1+k)tan2x4tanx1+k=0 has real roots, then

(a). k25

(b). tan(x1+x2)=2

(c). for k=2,x1=π4

(d). for k=1,x1=0

Show Answer Answer: (a, b, c, d)

12. If p,q{1,2,3,4}, the number of equations of the form px2+qx+1=0 having real roots is

(a). 15

(b). 9

(c). 7

(d). 8

Show Answer Answer: (c)

13. In PQRR=π2. If tanp2&tanQ2 are the roots of the equation ax2+bx+c=0(a0) then

(a). a+b=c

(b). b+c=0

(c). a+c=b

(d). b=c

Show Answer Answer: (a)