Unit 06 Chemical Thermodynamics

Thermodynamics: Means flow of heat

One of the fundamental subject in physical chemistry

It’sa science of macroscopic properties i.e. properties of matter in bulk

It deals with energy changes accompanying all types of physical and chemical processes

It predicts the feasibility or spontaneity of a process, including a chemical reaction, under a given set of conditions

It helps to determine the extent to which a process can proceed before attainment of equilibrium

Terms used in Thermodynamics

System : Part of universe chosen for thermodynamic studies.

Surroundings: Remaining universe other than the system.

Universe = system + surroundings

Boundary: Real or imaginary surface that separates the system from its surroundings

Classification of Systems

On the basis of possibility of movement of matter and energy in or out of the system.

(a) Open System: It can exchange both matter and energy with its surroundings.

e.g. tea kept in on open vessel.

(b) Closed System : It can exchange only energy with its surroundings but not matter.

e.g. tea kept in closed vessel.

(c) Isolated System : It can neither exchange matter nor energy with its surroundings.

e.g. tea kept in thermos flask.

State of the System

A system is said to be in a definite state if each of its measurable property has a definite value.

A system is described by specifying some or all of its p,V,T and composition.

State of the system is specified by state functions or state variables.

Types of Function / Variables

(a) State Function

A physical quantity whose value depends upon the state of the system and does not depend upon the path by which the state has been attained.

e.g. p, V,T, internal energy, enthalpy, entropy

(b) Path Function

A physical quantity which depends on the path by which change is brought.

e.g. work and heat.

Macroscopic Properties of the System

(a) Intensive Properties

Properties which do not depend upon the amount of the substance. e.g. pressure, density, temperature, surface tension, boiling point, refractive index etc.

(b) Extensive Properties

Properties which depend upon the amount of the substance.

e.g. volume, mass, heat capacity, number of moles etc.

 Extensive property  Extensive property = Intensive property e.g.  Mass  Volume = Density

(c) Molar Property (xm)

Value of an extensive property ’ x ’ of the system for 1 mole of the substance.

xm=xn (Independent of the amount of matter (n) )

All the molar properties are intensive properties.

Types of Processes

(a) Reversible Process

A process which is carried out infinitesimally slowly by a series of steps such that system and surroundings are always in near equilibrium with each other.

At any moment, the process can be reversed by an infinitesimal change.

(b) Irreversible Process

A process which cannot be reversed by small change.

Irreversible processes are carried out at finite rates.

(c) Adiabatic Process

A process during which no heat can flow in or out of the system. dq=0

(d) Isothermal Process

It is carried out at constant temperature

dT=0

(e) Isobaric Process

It is carried out at constant pressure

dp=0

(f) Isochoric Process

During the process, volume of the system remains constant

dV=0

pV graph for various thermodynamic processes

(g) Cyclic Process

When a system undergoes a series of changes and finally returns to its initial state.

Common modes of transfer of energy between system and surroundings

Heat (q)

Work (w)

Internal Energy (U)

It is the sum of all types of energies, a system may have like chemical, electrical, mechanical or any other type of energy.

It is a state function and an extensive property

Absolute measurement of U is not possible so change in internal energy, ΔU is considered.

ΔU=U1Ui

where, Uf and Ui are the internal energies of final and initial states, respectively.

U of the system may change, when

Heat passes into or out of the system

Work is done on or by the system

Matter enters or leaves the system

At constant volume

ΔU=q

qv= heat absorbed or evolved at const. volume

Sign Convention

If energy is released, ΔU=ve

If energy is absorbed, ΔU=+ve

Work(w)

A form of energy transferred from system to the surroundings or from surroundings to the system due to difference in some property (other than temperature) between system and surroundings

Types of work

Mechanical work (due to difference in pressure)

work of expansion or compression or p V work

Mechanical work = force x displacement

Electrical work (due to difference in electrical potential) =Emfx quantity of electricity passed

Sign Convention

If work is done on the system, w=+ve (compression)

If work is done by the system, w=ve (expansion)

Heat

It is a form of energy exchanged between system and surroundings due to difference in temperature between system and surroundings

Sign Convention

If heat is absorbed (endothermic reaction), q=+ve

If heat is released (exothermic reaction), q=ve

Units of work, heat and energy

SI unit of work =J or Nm1

Cgs unit of work = erg or dyne cm1

1 J=107ergs=0.239cal

1 kJ=1000 J

1Latm=101.3 J

1cal=4.184 J=4.184×107erg=41.293 atm cm3

1eV=1.602×1019 Jmolecule1=96.48 kJ mol1

=23.06kcalmol1

=8065.5 cm1

1 cal >1 J>1 erg >1 ev

Work done (w) in various processes

Work of expansion / compression or pV work

a) Work done in irreversible isothermal expansion against a constant external pressure (pext )

w=pext ΔV=pext (V2V1)

V2 and V1 represent the final and initial volumes, respectively

b) Wore done in isothermal reversible expansion of n moles of an ideal gas

w=2.303nRTlogV2V1=2.303nRTlogp1p2

(-ve sign has been used as it is work of expansion i.e. work done by the system)

c) Free Expansion (Expansion in vaccum)

Ideal gas: pext =0,w=0,ΔU=0,q=0

Real gas: pext =0,w=0

Work and heat are not state functions, they are path functions

First Law of Thermodynamics

The energy of an isolated system is constant. Mathematically

ΔU=q+w

This law is also known as law of conservation of energy i.e. energy can neither be created nor destroyed

For an ideal gas undergoing isothermal changes (ΔT=0),ΔU=0

Isothermal and Free Expansion of an Ideal Gas

pext =0

w=0

Also, q=0 and ΔU=0

1. For isothermal irreversible change

q=W=pext(V2V1)

2. For isothermal reversible change

q=w=nRTlnV2V1=2.303nRTlogV2V1

3. For adiabatic change, q=0

ΔU=Wad

Comparison of reversible, irreversible and adiabatic work

Wrev >Wireve >Wad 

For reversible expansion, pext  has maximum value (only infinitesimally smaller than pint  ), work done in reversible expansion is the maximum work for a given change in volume.

Enthalpy (H)

It is the heat evolved or absorbed at constant pressure.

It is a state function and an extensive property.

For exothermic reactions, ΔH=-ve; heat is evolved during the reaction

For endothermic reactions, ΔH=+ve; heat is absorbed from the surroundings

H=U+pV

ΔH=ΔU+pΔV (at const. pressure)

ΔH=qp (heat absorbed at constant pressure)

ΔU=qv (heat absorbed at constant volume)

Also,

ΔH=ΔU+ΔngRT

where, Δn9= difference between the number of moles of the gaseous products and those of the gaseous reactants.

The difference in ΔU and ΔH is insignificant for solids and liquids.

Heat capacity (C)

Amount of heat required to raise the temperature of the system by 1C or 1 K

C=qΔTCm Amount of Substance 

It is an extensive property

Units : JK1

Specific Heat Capacity (c)

Amount of heat required to raise the temperature of one gram (unit mass) of a substance by 1C or 1 K

It is an intensive property

Units : Jg1 K1

q=c×m×ΔT=CΔT

where, q= heat required to raise the temperature of a sample

c= specific heat capacity of the substance

m= mass of the sample; ΔT = temperature change

Specific heat capacity of water is 1calg1 K1 or 4.184 J g1 K1

Molar heat capacity ( Cm)

Amount of heat required to raise the temperature of 1 mole of the substance by 1C or 1 K

Cm=Cn

where, C is the heat capacity of ’ n ’ moles of the substance.

Unit: J mol 1 K1

It is an intensive property

Types of Heat Capacities

Cv - heat capacity at constant volume

CP-heat capacity at constant pressure

For an ideal gas

CV=dU dT and Cp=dH dTCpCV=R (for 1 mole of an ideal gas) 

For n moles

CpCV=nRγ=CpCV(ratio of Cp/Cv represented by γ )

Importance of Cp and Cv

Ratio of Cp and Cv, represented by γ, is related to atomicity of the gas

CpCvγMonoatomic Gas5cal3cal1.67Diatomic Gas7cal5cal1.40Triatomic Gas8cal6cal1.33

Measurement of ΔU and ΔH

Since, ΔU=qN

So, ΔU is determined by measuring the heat lost or gained (qv) for the reaction or process in a closed vessel (constant volume) e.g. Bomb calorimeter.

ΔH=qp

In this case, the heat lost or gained (qp) is determined when the reaction is carried out in an open vessel.

If reaction involves only solids & liquids or Δng=0, then ΔH=ΔU

For a cyclic process : ΔU=0,ΔH=0

During isothermal expansion of an ideal gas, ΔU=0,ΔT=0 and ΔH=0. Thus, it is an isoenthalpic process.

Enthalpy change of the reaction (ΔrH)

The amount of heat absorbed or evolved in a chemical reaction when moles of reactants and products being the same as indicated by the balanced chemical reaction.

Standard Conditions

Pressure =1 bar

Temperature = any specified temperature

The standard state of a substance at a specified temperature is its pure form at 1 bar.

Standard conditions are denoted by adding the superscript 0 or Θ to the symbol. e.g. ΔHP/ ΔH

Standard enthalpy of a reaction ΔrH

The enthalpy change accompanying the reaction when all the reactants and products are taken in their standard states ( 1 bar pressure and at any specified temperature, generally 298 K ).

Depending upon the nature of the reaction, enthalpy of the reaction is named accordingly.

Enthalpy of combustion, ΔcH

The enthalpy change when one mole of a substance is burnt completely in excess of oxygen.

Enthalpy of formation ΔrH

The enthalpy change when one mole of a substance is formed from its elements under given conditions of temperature and pressure.

Enthalpy of neutralization Δneut H

The enthalpy change when one gram equivalent of the acid is neutralized by a strong base.

Enthalpy of solution Δsol H

The enthalpy change when one mole of the substance is dissolved in a specified amount of the solvent.

Δsol H=Δlattice Hp+Δhyd H

For most of the ionic compounds

Δsol H=+ve

Enthalpy of Hydration Δhyd H

Amount of heat evolved or absorbed when one mole of an anhydrous salt combines with the required number of water molecules to form the hydrated salt.

Dissociation process of the compounds is endothermic

Solubility of most salts in H2O increases with rise of T

Enthalpy of atomization ΔaH :

The enthalpy change when one mole of a substance dissociates into gaseous atoms.

Enthalpy of Reaction

ΔrH0=ΣΔiH0 (products) ΣΔiH0 (reactants)

ΔfH0 is the standard enthalpy of formation. For elements in their most stable states ΔiH0 is taken as zero.

For example, the most stable states of oxygen, bromine, iodine are O2( g),Br2(l),I2( s)

whereas for carbon C (graphite), for sulphur S8 (rhombic)

ΔtH0 for all these substances is equal to zero.

Depending upon the type of process involving a phase change, the enthalpy change (for one mole of a substance) is named accordingly.

Enthalpy of fusion, Δtus H

Enthalpy change that accompanies melting of one mole of a solid substance at constant temperature and pressure.

Melting of a solid is endothermic process

Δfus H=+ ve (all)

Enthalpy of vaporization Δvap H

Amount of heat required to vaporize one mole of a liquid at constant temperature and pressure.

Enthalpy of sublimation Δsub H

Enthalpy change when one mole of a solid substance sublimes at a constant temperature and pressure.

Δsub H=Δfus H+Δvap H

Note: Magnitude of enthalpy change depends on the strength of the intermolecular interactions in the substance undergoing the phase transformations.

Hess’s Law of constant heat summation

the total enthalpy change accompanying a chemical reaction is the same whether the reaction takes place in one or more steps.

ΔH=ΔH1+ΔH2+ΔH3

When chemical equations are added, subtracted or multiplied, the enthalpy changes can also be added, subtracted or multiplied.

The sign of ΔrH gets reversed on reversing a chemical equation.

Bond enthalpy (Δbond H)

The amount of energy required to dissociate one mole of bonds present between the atoms in the gaseous molecules. Two separate terms are used in thermodynamics (i) bond dissociation enthalpy (ii) mean bond enthalpy.

Bond dissociation enthalpy is the change in enthalpy when one mole of covalent bonds of a gaseous compound is broken to form products in gas phase.

Mean bond enthalpy is the average value of bond dissociation enthalpy of a particular type of bond present in different compounds.

ΔrH=ΣB.Ereactant ΣB.Eproduct 

Units: kJ/mol

Calculation of lattice enthalpy using Born-Haber cycle

Lattice enthalpy (Δaltite H0) : is the enthalpy change which occurs when one mole of an ionic compound in crystalline state dissociates into its ions in gaseous state.

The sum of the enthalpy changes round a Born-Haber cycle is zero.

Enthalpy diagram for lattice enthalpy of NaCl (Born Haber cycle for NaCl).

Spontaneous process : a physical or chemical change that occurs on its own. It may or may not need initiation.

Non-spontaneous process : a process which cannot take place by itself nor by initiation.

Two factors which govern the spontaneity of a process:

  1. Tendency to attain minimum energy state.

  2. Tendency to attain maximum randomness or disorder.

First law of thermodynamics puts no restriction on the direction of heat flow or direction of any process.

The flow of heat is unidirectional from higher temperature to lower temperature.

Most of the processes occur spontaneously only in one direction under a given set of conditions of temperature and pressure.

Decrease in enthalpy is not the only criterion for spontaneity.

Entropy, S : is a measure of randomness or disorder of the system.

It is a state function i.e. path independent

Qualitatively, ΔS in a chemical reaction is estimated by a consideration of the structures of the species.

A crystalline solid will have the lowest entropy, whereas the gaseous state will have the highest entropy.

The order of randomness and thus, the entropy is:

Gas > liquid > solid

For a reversible change at constant temperature

ΔS=qrevT

qrev = heat absorbed or evolved at absolute temperature T

Unit: JK1 mol1

In achemical reaction:

ΔrS=ΣSproducts ΣSreactants 

Entropy changes during phase transformations

(a) Δtus S=Δtus HTm

Δtus H= enthalpy of fusion per mole

Tm= melting temperature in Kelvin

(b) Δvap S=Δvap HTb

Δfus H= enthalpy of vapourization per mole

Tb= boiling temperature in kelvin

(c) Δsub S=Δsub HT

Δsub H= enthalpy of sublimation at the temperature T.

For all spontaneous processes, the total entropy change must be positive

ΔStotal =ΔSsystem +ΔSsurr >0

ΔStotal =+ve Process is spontaneous

Stotal =ve Direct process is non-spontaneous; the reverse process is spontaneous.

When a system is in equilibrium, the entropy is maximum and the change in entropy, ΔS= 0 .

ΔU does not discriminate between reversible and irreversible process whereas ΔS does.

ΔU=0 (for both reversible & irreversible expansion for an ideal gas; under isothermal conditions)

ΔStotal >0 (for irreversible process) and ΔStotal =0 (for reversible process)

Second Law of Thermodynamics

For a spontaneous process in an isolated system, the change in entropy is positive. Or

It is impossible to convert heat completely into work without leaving some effects elsewhere.

Gibbs Energy, G

The maximum amount of energy available to a system, during a process, that can be converted into useful work.

It is a state function and an extensive property

Units: Jmol1

Gibbs Helmholtz Equation

ΔG=ΔHTΔS( at constant T and p)ΔG=TΔStotal 

ΔG gives a criteria for spontaneity at constant pressure and temperature

If, ΔG=ve(<0) Process is spontaneous.

If, ΔG=+ve(>0) Process is non-spontaneous

It, ΔG=0 Process is in equilibrium

ΔG0 is the Gibbs energy change for a process when all the reactants and products are in their standard states.

Relationship between equilibrium constant (K) and ΔG

ΔG0=2.303RTlogK

Relationship between electrical work done in the galvanic cell and G

ΔG=nFEcol 

Eenl = emf of the cell

n=n0. of moles of electrons involved

F= Faraday’s constanti.e. 96500Cmol1

If reactants and products are in their standard states

ΔG=nFEcell 0

E0= standard emf of the cell

Effects of signs of ΔH,ΔS and T on the spontaneity of a process

Sign of ΔH Sign of ΔS Value of T Spontaneity
- + Any Spontaneous
+ - Any Non-spontaneous
- - Low Spontaneous
- - High Non-spontaneous
+ + Low Non-spontaneous
+ + High spontaneous

Solved Examples

Question 1. How many calories are required to heat 40gram of argon from 40 to 100C at constant volume? ( R=2calK1 mol1 )

(a) 120

(b) 2400

(c) 1200

(d) 180

Show Answer

Solution: d

For a monoatomic gas, Cv=3calK1 mol1&Cp=5calK1 mol1,

40 gram of Argon =1 mole.

Cv= molar heat capacity at const. volume.

Heat required to raise the temperature from 40 to 100C at constant volume =3×(10040)

=3×60=180cal

Question 2. 4.48 L of an ideal gas at NTP requires 12.0 calories to raise its temperature by 15C at constant volume. The Cp of the gas is

(a) 3cal

(b) 4cal

(c) 7cal

(d) 6cal

Show Answer

Solution: d

n=4.4822.4qv=n×Cv×ΔT12=4.4822.4×Cv×15Cv=4calK1 mol1CpCv=RCp=R+Cv=2+4Cp=6calK1 mol1

Question 3. The standard enthalpy of formation of NH3 is 46.0 kJ mol1. If the enthalpy of formation of H2 from its atoms is 436 kJ mol1 and that of N2 is 712 kJ mol1, the average bond enthalpy of NH bond in NH3 is

(a) 1102 kJ mol1

(b) 964 kJ mol1

(c) +352 kJ mol1

(d) 1056 kJ mol1

Show Answer

Solution: c

Enthalpy of formation of NH3=46 kJ mol1

12 N2( g)+32H(g)NH3( g)

ΔiH=46 kJ mol1

H2( g)2H(g)

Δ0H=+436 kJ mol1

N2( g)2 N( g)

ΔH=+712kJmol1

ΔrH=ΣB.Ereactants ΣB.E.products 

ΔrH=12 B.E. (N2)+32 B.E. (H2) B.E. (NH3)

46=12×712+32×4363( NH)

(b)E. (NH)=+352 kJ mol1

  • There are 3 N-H bonds in NH3, so average bond enthalpy will be (B.E. of NH3)/3.

Question 4. The standard molar enthalpies of formation of cyclohexane (I) and benzene (I) at 25C are - 156 and +49 kJ mol1, respectively. The standard enthalpy of hydrogenation of cyclohexene (I) at 25C is 119 kJ mol1. The magnitude of the resonance energy is :

(a) 357 kJ mol1

(b) 152 kJ mol1

(c) 205 kJ mol1

(d) +152 kJ mol1

Show Answer

Solution: b

Enthalpy change for the hydrogenation of benzene should be three times the enthalpy of hydrogenation of cyclohexene

Δ4Hρ=3×ΔHρ

=3(119)=357 kJ mol1

On adding equations (2) and (4), we get

(5) 6C(s)+6H2( g) Δ6H0=308 kJ mol1

This reaction also gives the energy of formation of cyclohexane.

The difference in the enthalpy of formation calculated by these alternate paths is due to resonance stabilization of benzene.

Resonance energy of benzene =308(156)

=152 kJ mol1

Question 5. The enthalpy of formation of CO2( g),H2O(I) and propene (g) are 393.5,285.8 and 20.42 kJ mol1, respectively. The enthalpy of isomerization of cyclopropane to propene is 33.0 kJ mol1. The enthalpy change for combustion of cyclopropane is :

(a) 2058.32 kJ

(b) 2091.32 kJ

(c) +2058.32 kJ

(d) +2091.32 kJ

Show Answer

Solution: b

1. C(s)+O2( g)CO2( g) ΔiHP=393.5 kJ mol1

2. H2( g)+112O2( g)H2O(g) ΔiHP=285.8 kJ mol1

3. 3C(s)+3H2( g)C3H6( g) ΔiH=20.42 kJ mol1

4. CH3CH=CH2 ΔrH=33.0 kJ mol1

5. +92O23CO2+3H2OΔcH= ?

First, calculate the enthalpy of combustion of propene using Hess’s law.

i.e.

6. C3H6+92O23CO2+3H2OΔctH= ?

ΔcH=3(393.5)+3(285.8)20.42 =2058.32 kJ

Enthalpy of combustion of cyclopropane can be found on adding equations (4) and (6)

ΔcH=(2058.3233.0)kJ ΔcH=2091.32 kJ

Practice Questions

Question 1. For which of the process, ΔS is negative?

(a) H2( s)2H(g)

(b) N2( g,1 atm)N2( g,8 atm)

(c) 2SO3( g)2SO2( g)+O2( g)

(d) C(diamond) C(graphite) 

Show Answer Answer: (b)

Question 2. The favourable conditions for a spontaneous reaction are

(a) TΔS>ΔH,ΔH=+ve,ΔS=+ve

(b) TΔS>ΔH,ΔH=+ ve, ΔS= ve

(c) TΔS=ΔH,ΔH=ve,ΔS=ve

(d) TΔS=ΔH,ΔH=+ve,ΔS=+ve

Show Answer Answer: (a)

Question 3. Certain reaction is at equilibrium at 82C and the enthalpy change for this reaction is 21.3 kJ. The value of ΔS( in JK 1 mol1) for the reaction is

(a) 55.0

(b) 60.0

(c) 68.5

(d) 120.0

Show Answer Answer: (b)

Question 4. Which of the following thermodynamic relation is correct?

(a) dG=V dPS dT

(b) dU=P dV+T dS

(c) dH=V dP+T dS

(d) dG=V dP+S dT

Show Answer Answer: (a)

Question 5. For a gaseous reaction A+3 B2C,ΔH=90.0 kJ,ΔS=200.0JK1 at 400 K. What is ΔG for the reaction 12A+32BC at 400 K ?

(a) 5.0 kJ

(b) 10.0 kJ

(c) 15.0 kJ

(d) 20.0 kJ

Show Answer Answer: (a)

Question 6. The values of ΔH and ΔS for the reaction C(graphite )+CO2( g)2CO(g) are 170 kJ and 170JK1 respectively. This reaction will be spontaneous at

(a) 910 K

(b) 1110 K

(c) 510 K

(d) 710 K

Show Answer Answer: (b)

Question 7. A reaction is spontaneous at low temperature but non-spontaneous at high temperature. Which of the following is true for the reaction?

(a) ΔH>0,ΔS>0

(b) ΔH<0,ΔS>0

(c) ΔH>0,ΔS<0

(d) ΔH<0,ΔS<0

Show Answer Answer: (d)

Question 8. ΔG for a reaction is 46.06kcal/mole,Kp for the reaction at 300 K is

(a) 108

(b) 1022.22

(c) 1033.53

(d) none of these

Show Answer Answer: (c)

Question 9. The enthalpy change for the reaction, Zn(s)+2H+(aq)Zn2+(aq)+H2( g) is 154.4 kJ mol1. The formation of 2 g of hydrogen expands the system by 22.4 L at 1 atm pressure. The internal energy change of the reaction will be

(a) 156.kJ

(b) 152.1 kJ

(c) 154.4 kJ

(d) None of these is correct

Show Answer Answer: (a)

Question 10. Two moles of an ideal gas is expanded isothermally and reversibly from 1 litre to 10 litre at 300 K. The enthalpy change (in kJ ) for the process is

(a) 11.4 kJ

(b) 11.4 kJ

(c) 0 kJ

(d) 4.8 kJ

Show Answer Answer: (c)

Question 11. When 0.1 mole of a gas absorbs 41.75 J of heat at constant volume, the rise in temperature occurs equal to 20C. The gas must be

(a) triatomic

(b) diatomic

(c) polyatomic

(d) monoatomic

Show Answer Answer: (b)

Question 12. An insulated container is divided into two compartments. One compartment contains an ideal gas at a pressure P and temperature T while in the other compartment there is perfect vacuum. If a hole is made in the partition wall, which of the following will be true?

(a) ΔU=0

(b) w=0

(c) ΔT=0

(d) All the three are true

Show Answer Answer: (d)

Question 13. One mole of a non-ideal gas undergoes a change of state (2.0 atm,3.0 L,95 K)(4.0 atm,5.0 L,245 K ) with a change in internal energy, ΔU=30.0 L atm. The change in enthalpy (ΔH) of the process in L atm is

(a) 44.0

(b) 42.3

(c) 44.0

(d) not defined, because pressure is not constant

Show Answer Answer: (c)

Question 14. An ideal gas is allowed to expand both reversibly and irreversibly in an isolated system. If Ti is the initial temperature and Tt is the final temperature, which of the following statements is correct?

(a) (Tt)reve >(Tt)irev 

(b) Tt=Ti for both reversible and irreversible processes

(c) (Tt)ireve >(Tt)rev 

(d) Tt>Ti for reversible process but Tt=Ti for irreversible processes

Show Answer Answer: (b)

Question 15. One mole of an ideal gas expands freely and isothermally at 300 K from 10 litres to 100 litres. If ΔU=0, the value of ΔH is

(a) 10 kJ

(b) 200 kJ

(c) zero

(d) 300 kJ

Show Answer Answer: (c)

Question 16. Which one of the following equations does not correctly represent the first law of thermodynamics for the given process?

(a) Isothermal process: q=w

(b) Cyclic process: q=w

(c) Isochoric process : ΔU=q

(d) Adiabatic process : ΔU=w

Show Answer Answer: (d)

Question 17. When 100 g of water is electrolysed at constant pressure of 1 atm and temperatureof 25C, the work of expansion is

(a) 203.8 kJ

(b) 20.6 kJ

(c) 23.6 kJ

(d) 101.9 kJ

Show Answer Answer: (b)

Question 18. Work done in expansion of an ideal gas from 4dm3 to 6dm3 against a constant external pressure of 2.5 atm was used up to heat up 1 mole of water at 20C. The final temperature of water will be (Given: specific heat of water =4.184 J g1 K1 )

(a) 23.7C

(b) 24.7C

(c) 25.7C

(d) 26.7C

Show Answer Answer: (d)

Question 19. The bond dissociation energies of XY,X2 and Y2 (all diatomic molecules) are in the ratio 1:1:0.5 and Δ1H for the formation of XY is 200KJmol1. The bond dissociation energy of X2 will be

(a) 400 kJ mol1

(b) 800 kJ mol1

(c) 200 kJ mol1

(d) 100 kJ mol1

Show Answer Answer: (a)

Question 20. Under which of the following condition is the relation ΔH=ΔU+pΔV valid for a closed system?

(a) constant pressure

(b) constant temperature

(c) constant temperature and pressure

(d) constant temperature, pressure and composition

Show Answer Answer: (a)

Question 21. Given NH3( g)+3Cl2( g)NCl3( g)+3HCl(g);ΔH1

N2( g)+3H2( g)2NH3( g);ΔH2

H2( g)+Cl2( g)2HCl(g);ΔH3

The heat of formation of NCl3( g) in the terms of ΔH1,ΔH2 and ΔH3 is

(a) ΔiH=ΔH1ΔH2232ΔH3

(b) ΔiH=ΔH1+ΔH2232ΔH3

(c) ΔiH=ΔH1ΔH2232ΔH2

(d) None

Show Answer Answer: (a)

Question 22. Given that the enthalpy of formation of H2O is 68kcalmol1, the enthalpy of formation of OHions will be

(a) 34kcalmol1

(b) 81.7kcalmol1

(c) 27.4kcalmol1

(d) 54.3kcalmol1

Show Answer Answer: (d)

Question 23. H2( g)+1/2O2( g)H2O(I);ΔHρ=68kcal

K(s)+H2O(I)+aqKOH(aq)+1/2H2;ΔH0=48kcal

KOH(s)+aqKOH(aq);ΔH;=14kcal

From the above data, the standard heat of formation of KOH in kcal is :

(a) 68+4814

(b) 6848+14

(c) 6848+14

(d) 68+48+14

Show Answer Answer: (b)

Question 24. Given: CH4( g)+Cl2( g)CH3Cl(g)+HCl(g),ΔH=100.3 kJ

Bond energies : CH=413 kJ mol1

ClCl=243 kJ mol1HCl=431 kJ mol1

The energy of C - Cl bond will be

(a) 225.0 kJ mol1

(b) 425.6 kJ mol1

(c) 325.3 kJ mol1

(d) 261.0 kJ mol1

Show Answer Answer: (c)

Question 25. The bond energies of CC,C=C,HH and CH linkages are 350,600,400, and 410 kJ per mole respectively. The heat of hydrogenation of ethylene is

(a) 170 kJ mol1

(b) 260 kJ mol1

(c) 400 kJ mol1

(d) 450 kJ mol1

Show Answer Answer: (a)

Question 26. Enthalpy of CH4+1/2O2CH3OH is negative If enthalpy of combustion of methane and CH3OH are x and y respectively, then which relation is correct?

(a) x>y

(b) x<y

(c) x=y

(d) xy

Show Answer Answer: (b)

Question 27. When 1 mole of crystalline NaCl is obtained from sodium and chlorine gas, 410 kJ of heat is released. The heat of sublimation of sodium metal is 108 kJ mol1 and ClCl bond enthal py is 242 kJmol1. If the ionization energy of Na is 493.0 kJ mol1 and the electron affinity of chlorine is 368 kJmol1, the lattice energy of NaCl is

(a) 764 kJ mol1

(b) 764 kJ mol1

(c) 885 kJ mol1

(d) 885 kJ mol1

Show Answer Answer: (b)

Question 28. The lattice enthalpy and hydration enthalpy of four compounds are given below:

Compounds Lattice enthalpy
( in kJmol1 )
Hydration enthalpy
(in kJmol1 )
P +780 -920
Q +1012 -812
R +828 -878
S +632 -600

The pair of compounds which is soluble in water is

(a) P and Q

(b) Q and R

(c) R and S

(d) P and R

Show Answer Answer: (d)

Question 29. Given the following data:

Δ4H(C2H4)=12.5kcal

Heat of atomisation of C=171kcal

Heat of atomisation of H=521kcal

Bond energy of CH bond =99.3kcal

What is C=C bond energy?

(a) 140.7kcal

(b) 36kcal

(c) 40kcal

(d) 76kcal

Show Answer Answer: (a)

Question 30. If an endothermic reaction occurs spontaneously at constant T and P, then which of the following is true?

(a) ΔG>0

(b) ΔH<0

(c) ΔS>0

(d) ΔS<0

Show Answer Answer: (c)

Question 31. For the given reaction H2( g)+Cl2( g)+(aq)2H+(aq)+2Cl(aq),ΔG0=262.4 kJ The value of Gibbs energy of formation (ΔiG0) for the ion Cl(aq), therefore, will be

(a) 131.2 kJ mol1

(b) +131.2 kJ mol1

(c) 262.4 kJ mol1

(d) +262.4 kJ mol1

Show Answer Answer: (a)

Question 32. Consider the reaction

4NO2( g)+O2( g)2 N2O5( g)ΔrH=111 kJ

If N2O5( s) is formed instead of N2O5( g) in the above reaction, the Δ4Hvalue will be : (given, ΔH of sublimation for N2O5 is 54 kJ mol1 )

(a) +219 kJ

(b) 219 kJ

(c) 165 kJ

(d) +54 kJ

Show Answer Answer: (b)

Question 33. Oxidizing power of chlorine in aqueous solution can be determined by the parameters indicated below:

1/2Cl2( g)1/2Δdiss HpCl(g)ΔeqHpCl(g)ΔndyHpCl(aq)

The energy involved in the conversion of 1/2Cl2( g) to Cl(aq)

(Using the data, Δdiss HCl2=240 kJ/mol,ΔeqHcl=349 kJ/mol,ΔndyHCl0=381 kJ/mol ) will be

(a) 610 kJ mol1

(b) 850 kJ mol1

(c) +120 kJ mol1

(d) +152 kJ mol1

Show Answer Answer: (a)

Question 34. Standard entropy of X2,Y2 and XY3 are 60,40 and 50 J K1 mol1, respectively. For the reaction 12X2+32Y2XY3ΔH=30KJ, to be at equilibrium, the temperature will be

(a) 500 K

(b) 750 K

(c) 1000 K

(d) 1250 K

Show Answer Answer: (b)

Question 35. For a particular reversible reaction at temperature T,ΔH and ΔS were found to be both +ve. If T e is the temperature at equilibrium, the reaction would be spontaneous when

(a) T=Te

(b) Te>T

(c) T>Te

(d) Te is 5 times T

Show Answer Answer: (c)

Question 36. The value of enthalpy change (ΔH) for the reaction

C2H5OH(I)+3O2( g)2CO2( g)+3H2O(I)

at 27C is 1366.5 kJ mol1. The value of internal energy change for the above reaction at this temperature will be :

(a) 1364.0 kJ

(b) 1361.5 kJ

(c) 1371.5 kJ

(d) 1369.0 kJ

Show Answer Answer: (a)

Question 37. The incorrectexpression among the following is:

(a) K=eΔG0RT

(b) ΔGsystem ΔStotal =T

(c) In isothermal process, wreversibe =nRTlnVfVi

(d) InK=ΔHρTΔS0RT

Show Answer Answer: (d)

Question 38. A gas present in a cylinder fitted with a frictionless piston expands isothermally against a constant pressure of 1 bar from a volume of 2 L to 12 L. In doing so, it absorbs 820 J heat from the surrounding. The change in internal energy during the process is :

(a) 180 J

(b) 18 J

(c) +1820 J

(d) +920 J

Show Answer Answer: (a)

Question 39. A system containing an ideal gas was subjected to a number of changes as shown in the pV diagram. In the following cyclic process, A to F specify the type of change taking place from B to C. given that the

Temperature at A,B and F=T1

Temperature at C,D and E=T2 T2<T1

(a) Isochoric and isothermal (pressure falls)

(b) Adiabatic compression, temperature increases to T1

(c) Adiabatic expansion, temperature fall to T2

(d) Isochoric and isothermal (pressure increases)

Show Answer Answer: (c)

Question 40. In the reactions

I: H22H ΔH=436 kJ

II: H2+12O2H2O ΔH=241.81 kJ

III : 2H+1/2O2H2O ΔH= ?

H2O can be formed either by II or III. Ratio of enthalpy change in III to II is :

(a) 2.8

(b) 1.2

(c) 0.36

(d) 0.82

Show Answer Answer: (a)


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