Chapter 01 Number Systems Exercise-05

EXERCISE 1.5

1. Find :

(i) 6412

(ii) 3215

(iii) 12513

Show Answer

Solution

(i)

6412=(26)12=22=4=26×12[(am)n=amm!](16)34=(24)34(iii)=23=8

=25×23[(am)n=ammn]

2. Find:

(i) 932

(ii) 3225

(iii) 1634

(iv) 12513

Show Answer

Solution

(ii)

3215=(25)15=(2)5×15=21=2

=24×34[(am)n=amm][(am)n=amm](125)13(iv)=1(125)13=23=8

(125)13=(53)13

=53×13[(am)n=amm]=153×13=51=5=15

[am=1am]

3. Simplify:

(i) 223215

(ii) (133)7

(iii) 11121114

(iv) 712812

Show Answer

Solution

(i)

223215=223+15[aman=am+n]=210+315=21315

(ii)

(133)7=133×7[(am)n=amm]=1321[1am=am]

(iii)

11121114=111214[aman=amn]=11214=1114

(iv)

712812=(7×8)12[ambm=(ab)m]=(56)12



Table of Contents