Chapter 01 Number Systems Exercise-02

EXERCISE 1.2

1. State whether the following statements are true or false. Justify your answers.

(i) Every irrational number is a real number.

(ii) Every point on the number line is of the form m, where m is a natural number.

(iii) Every real number is an irrational number.

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Solution

(i) True; since the collection of real numbers is made up of rational and irrational numbers.

(ii) False; as negative numbers cannot be expressed as the square root of any other number.

(iii) False; as real numbers include both rational and irrational numbers. Therefore, every real number cannot be an irrational number.

2. Are the square roots of all positive integers irrational? If not, give an example of the square root of a number that is a rational number.

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Solution

If numbers such as 4=2,9=3 are considered,

3. Show how 5 can be represented on the number line.

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Solution

We know that,

4=2

5=(2)2+(1)2

Show howAnd,

Mark a point ’ A ’ representing 2 on number line. Now, construct AB of unit length perpendicular to OA. Then, taking O as centre and OB as radius, draw an arc intersecting number line at C.

C is representing 5.

4. Classroom activity (Constructing the ‘square root spiral’) : Take a large sheet of paper and construct the ‘square root spiral’ in the following fashion. Start with a point O and draw a line segment OP1 of unit length. Draw a line segment P1P2 perpendicular to OP1 of unit length (see Fig. 1.9). Now draw a line segment P2P3 perpendicular to OP2. Then draw a line segment P3P4 perpendicular to OP3. Continuing in this manner, you can get the line segment Pn1Pn by

Fig. 1.9 : Constructing square root spiral drawing a line segment of unit length perpendicular to OPn1. In this manner, you will have created the points P2,P3,.,Pn,, and joined them to create a beautiful spiral depicting 2,3,4,

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Solution

Construct the “square root spiral”.

Step 1. On a large sheet of paper, mark a point O and draw a line segment OP1 of unit length.

Step 2. Draw a line segment P1P2 perpendicular to OP1 of unit length and join OP2.

Here, OP2 is of length 2 units. As from Pythagoras theorem: (OP2)2=(P1P2)2+(OP1)2

Step 3. Draw a line segment P2P3 perpendicular to OP2 of unit length and join OP3.

Here, OP3 is of length 3 units. As from Pythagoras theorem: (OP3)2=(P2P3)2+(OP2)2 Step 4. Repeat the steps to get the points P4,P5,P6, and join them with O to obtain 4,5,6,

Hence, the ‘square root spiral’ is constructed.



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