Work Power Energy Question 2
Question 2 - 2024 (29 Jan Shift 1)
The potential energy function (in $J$ ) of a particle in a region of space is given as $U=\left(2 x^{2}+3 y^{3}+2 z\right)$. Here $x, y$ and $z$ are in meter. The magnitude of $x$ - component of force (in $N$ ) acting on the particle at point $P(1,2,3) m$ is :
(1) 2
(2) 6
(3) 4
(4) 8
Show Answer
Answer: (3)
Solution:
Given $U=2 x^{2}+3 y^{3}+2 z$
$F _x=-\frac{\partial U}{\partial x}=-4 x$
At $x=1$ magnitude of $F _x$ is $4 N$
