The given figure represents two isobaric processes for the same mass of an ideal gas, then
(1) $P _2 \geq P _1$
(2) $P _2>P _1$
(3) $P _1=P _2$
(4) $P _1>P _2$
$PV=nRT$
$V=\left(\frac{nR}{P}\right) T$
Slope $=\frac{nR}{P}$
Slope $\propto \frac{1}{P}$
(Slope $) _2>(\text { Slope }) _1$
$P _2<P _1$
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