Rotational Motion Question 3
Question 3 - 2024 (27 Jan Shift 1)
Four particles each of mass $1 kg$ are placed at four corners of a square of side $2 m$. Moment of inertia of system about an axis perpendicular to its plane and passing through one of its vertex is $kgm^{2}$.
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Answer: (16)
Solution:
$$ \begin{aligned} & I=m a^{2}+m a^{2}+m(\sqrt{2 a})^{2} \\ & =4 m a^{2} \\ & =4 \times 1 \times(2)^{2}=16 \end{aligned} $$
