The distance between object and its two times magnified real image as produced by a convex lens is $45 cm$.
The focal length of the lens used is $cm$.
$\frac{v}{u}=-2$
$v=-2 u$
$v-u=45$
$\Rightarrow u=-15 cm$
$v=30 cm$
$\frac{1}{f}=\frac{1}{v}-\frac{1}{u}$
$f=+10 cm$
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