Ray Optics Question 5
Question 5 - 2024 (29 Jan Shift 1)
A convex mirror of radius of curvature $30 cm$ forms an image that is half the size of the object. The object distance is :
(1) $-15 cm$
(2) $45 cm$
(3) $-45 cm$
(4) $15 cm$
Show Answer
Answer: (1)
Solution:
Given $R=30 cm$
$f=R / 2=+15 cm$
Magnification $(m)= \pm \frac{1}{2}$
For convex mirror, virtual image is formed for real object.
Therefore, $m$ is $+ve$
$\frac{1}{2}=\frac{f}{f-u}$
$u=-15 cm$
