Ray Optics Question 4
Question 4 - 2024 (27 Jan Shift 1)
Two immiscible liquids of refractive indices $\frac{8}{5}$ and $\frac{3}{2}$ respectively are put in a beaker as shown in the figure. The height of each column is $6 cm$. A coin is placed at the bottom of the beaker. For near normal vision, the apparent depth of the coin is $\frac{\alpha}{4} cm$. The value of $\alpha$ is
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Answer: (31)
Solution:
$h _{upp}=\frac{h _1}{\mu _1}+\frac{h _2}{\mu _2}=\frac{6}{3 / 2}+\frac{6}{8 / 5}=4+\frac{15}{4}=\frac{31}{4} cm$
