The distance between object and its 3 times magnified virtual image as produced by a convex lens is $20 cm$. The focal length of the lens used is $cm$.
$v=3 u$
$v-u=20 cm$
$2 u=20 cm$
$u=10 cm$
$\frac{1}{(-30)}-\frac{1}{(-10)}=\frac{1}{f}$
$f=15 cm$
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