Oscillations Question 6
Question 6 - 2024 (30 Jan Shift 2)
A simple pendulum is placed at a place where its distance from the earth’s surface is equal to the radius of the earth. If the length of the string is $4 m$, then the time period of small oscillations will be s. [ take $\left.g=\pi^{2} ms^{-2}\right]$
Show Answer
Answer: (8)
Solution:
Acceleration due to gravity $g^{\prime}=\frac{g}{4}$
$T=2 \pi \sqrt{\frac{4 \ell}{g}}$
$T=2 \pi \sqrt{\frac{4 \times 4}{g}}$
$T=2 \pi \frac{4}{\pi}=8 s$
