Motion In One Dimension Question 3
Question 3 - 2024 (01 Feb Shift 2)
A particle initially at rest starts moving from reference point. $x=0$ along $x$-axis, with velocity $v$ that varies as $v=4 \sqrt{xm} / s$. The acceleration of the particle is $ms^{-2}$.
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Answer: (8)
Solution:
$V=4 \sqrt{x}$
$a=V \frac{dv}{dx}$
$=4 \sqrt{x} \times 4 \times \frac{1}{2} x^{-1 / 2}=8 m / s^{2}$
