Experimental Physics Question 5
Question 5 - 2024 (30 Jan Shift 2)
If 50 Vernier divisions are equal to 49 main scal divisions of a travelling microscope and on smallest reading of main scale is $0.5 mm$, th Vernier constant of travelling microscope is:
(1) $0.1 mm$
(2) $0.1 cm$
(3) $0.01 cm$
(4) $0.01 mm$
Show Answer
Answer: (4)
Solution:
$50 V+S=49 S+S$
$S=50(S-V)$
$.5=50(S-V)$
$S-V=\frac{0.5}{50}=\frac{1}{100}=0.01 mm$
