Electrostatics Question 3
Question 3 - 2024 (01 Feb Shift 2)
Suppose a uniformly charged wall provides a uniform electric field of $2 \times 10^{4} N / C$ normally. A charged particle of mass $2 g$ being suspended through a silk thread of length $20 cm$ and remain stayed at a distance of $10 cm$ from the wall. Then the charge on the particle will be $\frac{1}{\sqrt{x}} \mu C$ where $x=$ [use $g=10 m / s^{2}$ ]
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Answer: (3)
$\sin \theta=\frac{10}{20}=\frac{1}{2}$
$\theta=30^{\circ}$
$\tan \theta=\frac{qE}{mg}$
$\tan 30^{\circ}=\frac{q \times 2 \times 10^{4}}{1 \times 10^{-3} \times 10}$
$\frac{1}{\sqrt{3}}=q \times 10^{6}$
$q=\frac{1}{\sqrt{3}} \times 10^{-6} C$
$x=3$
