Electrostatics Question 12
Question 12 - 2024 (29 Jan Shift 2)
An electric field is given by $(6 \hat{i}+5 \hat{j}+3 \hat{k}) N / C$. The electric flux through a surface area $30 \hat{i} m^{2}$ lying in YZplane (in SI unit) is :
(1) 90
(2) 150
(3) 180
(4) 60
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Answer: (3)
$\overrightarrow{E}=6 \hat{i}+5 \hat{j}+3 \hat{k}$
$\overrightarrow{A}=30 \hat{i}$
$\phi=\overrightarrow{E} \cdot \overrightarrow{A}$
$\phi=(6 \hat{i}+5 \hat{j}+3 \hat{k}) \cdot(30 \hat{i})$
$\phi=6 \times 30=180$