Electromagnetic Induction Question 5
Question 5 - 2024 (29 Jan Shift 1)
A square loop of side $10 cm$ and resistance $0.7 \Omega$ is placed vertically in east-west plane. A uniform magnetic field of $0.20 T$ is set up across the plane in north east direction. The magnetic field is decreased to zero in $1 s$ at a steady rate. Then, magnitude of induced emf is $\sqrt{x} \times 10^{-3} V$. The value of $x$ is
Show Answer
Answer: (2)
Solution:
$$ \begin{aligned} & \overrightarrow{A}=(0.1)^{2} \hat{j} \\ & \overrightarrow{B}=\frac{0.2}{\sqrt{2}} \hat{i}+\frac{0.2}{\sqrt{2}} \hat{j} \end{aligned} $$
Magnitude of induced emf
$c=\frac{\Delta \phi}{\Delta t}=\frac{\overrightarrow{B} \cdot \overrightarrow{A}-0}{l}=\sqrt{2} \times 10^{-3} V$
