Atomic Physics Question 11
Question 11 - 2024 (31 Jan Shift 1)
The mass defect in a particular reaction is $0.4 g$. The amount of energy liberated is $n \times 10^{7} kWh$, where $n=$[^0]
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Answer: (1)
Solution:
$$ \begin{aligned} & E=\Delta mc^{2} \\ & =0.4 \times 10^{-3} \times\left(3 \times 10^{8}\right)^{2} \\ & =3600 \times 10^{7} kWs \\ & =\frac{3600 \times 10^{7}}{3600} kWh=1 \times 10^{7} kWh \end{aligned} $$
