Structure Of Atom Question 7
Question 7 - 2024 (27 Jan Shift 2)
Total number of ions from the following with noble gas configuration is _________.
$Sr^{2+}(Z=38), Cs^{+}(Z=55), La^{2+}(Z=57) Pb^{2+}$
$(Z=82), Yb^{2+}(Z=70)$ and $Fe^{2+}(Z=26)$
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Answer (3)
Solution
Noble gas configuration $=n s^{2} n p^{6}$
$$ \begin{aligned} & {\left[Sr^{2+}\right]=[Kr]} \\ & {\left[Cs^{+}\right]=[Xe]} \\ & {\left[Yb^{2+}\right]=[Kr] 4 d^{10} 4 f^{14} 5 s^{2} 5 p^{6}} \\ & {\left[La^{2+}\right]=[Xe] 5 d^{1}} \\ & {\left[Pb^{2+}\right]=[Xe] 4 f^{14} 5 d^{10} 6 s^{2}} \\ & {\left[Fe^{2+}\right]=[Ar] 3 d^{6}} \end{aligned} $$
