Solutions Question 2
Question 2 - 2024 (01 Feb Shift 2)
Mass of ethylene glycol (antifreeze) to be added to $18.6 kg$ of water to protect the freezing point at $-24^{\circ} C$ is __________ $kg$ (Molar mass in $gmol^{-1}$ for ethylene glycol $62, K _f$ of water $=1.86 K kg mol^{-1}$ )
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Answer (15)
Solution
$\Delta T _f=iK _f \times$ molality
$24=(1) \times 1.86 \times \frac{W}{62 \times 18.6}$
$W=14880 gm$
$=14.880 kg$
