Redox Reactions Question 7
Question 7 - 2024 (29 Jan Shift 2)
If $50 mL$ of $0.5 M$ oxalic acid is required to neutralise $25 mL$ of $NaOH$ solution, the amount of $NaOH$ in $50 mL$ of given $NaOH$ solution is ___________ g.
Show Answer
Answer (4)
Solution
Equivalent of Oxalic acid $=$ Equivalents of $NaOH$
$50 \times 0.5 \times 2=25 \times M \times 1$
$M _{NaOH}=2 M$
$W _{NaOH}$ in $50 ml=2 \times 50 \times 40 \times 10^{-3} g=4 g$
