Electrochemistry Question 2
Question 2 - 2024 (01 Feb Shift 2)
The amount of electricity in Coulomb required for the oxidation of $1 mol^{2}$ of $H _2 O$ to $O _2$ is _________ $\times 10^{5} C$.
Show Answer
Answer (2)
Solution
$2 H _2 O \rightarrow O _2+4 H^{+}+4 e^{-}$
$\frac{W}{E}=\frac{Q}{96500}$
mole $\times$ n-factor $=\frac{Q}{96500}$
$1 \times 2=\frac{Q}{96500}$
$Q=2 \times 96500 C$
$=1.93 \times 10^{5} C$
