Chemical Kinetics Question 9

Question 9 - 2024 (31 Jan Shift 1)

Integrated rate law equation for a first order gas phase reaction is given by (where $P _i$ is initial pressure and $P _t$ is total pressure at time $t$ )

(1) $k=\frac{2.303}{t} \times \log \frac{P _i}{\left(2 P _i-P _t\right)}$

(2) $k=\frac{2.303}{t} \times \log \frac{2 P _i}{\left(2 P _i-P _t\right)}$

(3) $k=\frac{2.303}{t} \times \log \frac{\left(2 P _i-P _t\right)}{P _i}$

(4) $k=\frac{2.303}{t} \times \frac{P _i}{\left(2 P _i-P _t\right)}$

Show Answer

Answer (1)

Solution

$A \rightarrow B+C$

$\begin{array}{lll}P _i & 0 & 0\end{array}$

$P _i-x$ $X$ $x$

$P _t=P _i+x$

$P _i-x=P _i-P _t+P _i$

$=2 P _i-P _t$

$K=\frac{2.303}{t} \log \frac{P _i}{2 P _i-P _t}$