Waves And Sound Question 2
Question 2 - 25 January - Shift 1
The distance between two consecutive points with phase difference of $60^{\circ}$ in a wave of frequency $500 Hz$ is $6.0 m$. The velocity with which wave is traveling is______ $km / s$
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Answer: (18)
Solution:
Formula: Phase difference
$\Delta \phi=\frac{2 \pi}{\lambda} \Delta x$
$\frac{\pi}{3}=\frac{2 \pi}{\lambda}(6 m)$
$\lambda=36 m$
$V=f \lambda=(500 Hz)(36 m)$
$=18000 m / s=18 km / s$
