Thermal Properties Of Matter Question 2
Question 2 - 30 January - Shift 2
A faulty thermometer reads $5^{\circ} C$ in melting ice and $95^{\circ} C$ in steam. The correct temperature on absolute scale will be $K$ when the faulty thermometer reads $41^{\circ} C$.
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Answer: (313)
Solution:
Formula: Liquid Thermometer
$\frac{41^{\circ}-5^{\circ}}{95^{\circ}-5^{\circ}}=\frac{C-0^{\circ}}{100^{\circ}-0^{\circ}}$
$\Rightarrow C=\frac{36}{90} \times 100=40^{\circ} C=313 K$