Semiconductors Question 8
Question 8 - 30 January - Shift 2
The output $Y$ for the inputs $A$ and $B$ of circuit is given by
Truth table of the shown circuit is :
$A$ | $B$ | $Y$ |
---|---|---|
0 | 0 | 1 |
(1) $0 \begin{matrix} 0 & 1 & 1\end{matrix} $
1 | 0 | 1 |
---|
1 | 1 | 0 |
---|
$A$ | $B$ | $Y$ |
---|---|---|
0 | 0 | 1 |
(2) $0 \begin{matrix} 0 & 1 & 0\end{matrix} $
1 | 0 | 0 |
---|
$\begin{matrix} 1 & 1 & 1\end{matrix} $
$A$ | $B$ | $Y$ |
---|---|---|
0 | 0 | 0 |
(3) $0 \begin{matrix} 0 & 1 & 1\end{matrix} $
1 | 0 | 1 |
---|
$\begin{matrix} 1 & 1 & 1\end{matrix} $
$A$ | $B$ | $Y$ |
---|---|---|
0 | 0 | 0 |
(4) $0 \begin{matrix} 0 & 1 & 1\end{matrix} $
$\begin{matrix} 1 & 0 & 1\end{matrix} $
1 | 1 | 0 |
---|
Show Answer
Answer: (4)
Solution:
Given circuit represent XOR