Semiconductors Question 8

Question 8 - 30 January - Shift 2

The output $Y$ for the inputs $A$ and $B$ of circuit is given by

Truth table of the shown circuit is :

$A$ $B$ $Y$
0 0 1

(1) $0 \begin{matrix} 0 & 1 & 1\end{matrix} $

1 0 1
1 1 0
$A$ $B$ $Y$
0 0 1

(2) $0 \begin{matrix} 0 & 1 & 0\end{matrix} $

1 0 0

$\begin{matrix} 1 & 1 & 1\end{matrix} $

$A$ $B$ $Y$
0 0 0

(3) $0 \begin{matrix} 0 & 1 & 1\end{matrix} $

1 0 1

$\begin{matrix} 1 & 1 & 1\end{matrix} $

$A$ $B$ $Y$
0 0 0

(4) $0 \begin{matrix} 0 & 1 & 1\end{matrix} $

$\begin{matrix} 1 & 0 & 1\end{matrix} $

1 1 0
Show Answer

Answer: (4)

Solution:

Given circuit represent XOR