Motion In Two Dimensions Question 6
Question 6 - 31 January - Shift 1
The speed of a swimmer is $4 km h^{-1}$ in still water.
If the swimmer makes his strokes normal to the flow of river of width $1 km$, he reaches a point $750 m$ down the stream on the opposite bank.
The speed of the river water is $km h^{-1}$.
Show Answer
Answer: (3)
Solution:
Formula: Crossing River
time to cross the River width $\omega=1000 m$
is $=\frac{1 km}{4 km / h}$
Drift $x=Vm / g \times t$
Where $Vm / g$ is velocity of River w.r. to ground.
