Magnetic Effects Of Current Question 4
Question 4 - 24 January - Shift 2
A single turn current loop in the shape of a right angle triangle with sides $5 cm, 12 cm, 13 cm$ is carrying a current of $2 A$. The loop is in a uniform magnetic field of magnitude $0.75 T$ whose direction is parallel to the current in the $13 cm$ side of the loop. The magnitude of the magnetic force on the $5 cm$ side will be $\frac{x}{130}$ N. The value of $x$ is
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Answer: (9)
Solution:
Formula: Magnetic field due to a straight wire
Force on $5 cm$ side is
$|\overrightarrow{{}F}|=ILB \sin \theta$
$=(2)(5 \times 10^{-2}) \times \frac{3}{4} \times \frac{12}{13}=\frac{9}{130} N$
So, $x=9$
