Magnetic Effects Of Current Question 23
Question 23 - 01 February - Shift 2
A square shaped coil of area $70 cm^{2}$ having 600 turns rotates in a magnetic field of $0.4 wbm^{-2}$, about an axis which is parallel to one of the side of the coil and perpendicular to the direction of field. If the coil completes 500 revolution in a minute, the instantaneous emf when the plane of the coil is inclined at $60^{\circ}$ with the field, will be $V$. (Take $\pi=\frac{22}{7}$ )
Show Answer
Answer: (44)
Solution:
Formula: Magnetic field due to a straight wire
$N=600, A=70 \times 10^{-4} m^{2}, B=0.4 T$
$\omega=\frac{500 \times 2 \pi}{60}=\frac{100 \pi}{6} rad / s$
$E=NAB \omega \sin \omega t$ is angle $b / w \overrightarrow{{}A} ~\&~ \overrightarrow{{}B}$
$=600 \times 70 \times 10^{-4} \times 0.4 \times \frac{100 \pi}{6} \times \frac{1}{2}$
$=44 V$
