Laws Of Motion Question 9
Question 9 - 30 January - Shift 2
A stone tied to $180 cm$ long string at its end is making 28 revolutions in horizontal circle in every minute. The magnitude of acceleration of stone is $\frac{1936}{x} ms^{-2}$. The value of $x$
$(.$ Take $.\pi=\frac{22}{7})$
Show Answer
Answer: (125)
Solution:
Formula: Centripetal Force
$a=\omega^{2} R=(\frac{28 \times 2 \pi}{60})^{2} \times 1.8$
$=(\frac{56}{60} \times \frac{22}{7})^{2} \times 1.8$
$=\frac{(44)^{2}}{225} \times 1.8$
$=\frac{1936 \times 1.8}{225}$
$x=125$
