Electromagnetic Waves Question 2

Question 2 - 24 January - Shift 2

The electric field and magnetic field components of an electromagnetic wave going through vacuum

is described by

$E_x=E_0 \sin (kz-\omega t)$

$B_y=B_0 \sin (kz-\omega t)$

Then the correct relation between $E_0$ and $B_0$ is given by

(1) $kE_0=\omega B_0$

(2) $E_0 B_0=\omega k$

(3) $\omega E_0=kB_0$

(4) $E_0=kB_0$

Show Answer

Answer: (1)

Solution:

Formula: Speed of light

$C=\frac{\omega}{k}=\frac{E_0}{B_0}$