Capacitance Question 1
Question 1 - 24 January - Shift 2
A parallel plate capacitor with air between the plate has a capacitance of $15 pF$. The separation between the plate becomes twice and the space between them is filled with a medium of dielectric constant 3.5. Then the capacitance becomes $\frac{x}{4} pF$. The value of $x$ is
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Answer: (105)
Solution:
Formula: Parallel Plate Capacitor
$C_0=\frac{\in_0 A}{d}=15 pF$
$C=\frac{K \in_0 A}{2 d}=\frac{3.5}{2} \times 15 pF=\frac{105}{4} pF$
