Atomic Physics Question 2
Question 2 - 24 January - Shift 2
A photon is emitted in transition from $n=4$ to $n=1$ level in hydrogen atom. The corresponding wavelength for this transition is
(given, $h=4 \times 10^{-15} eVs$ ) :
(1) $94.1 nm$
(2) $941 nm$
(3) $97.4 nm$
(4) $99.3 nm$
Show Answer
Answer: (1)
Solution:
Formula: Wavelength Corresponding To Spectral Lines
$ \frac{hc}{\lambda}=[1-\frac{1}{16}](13.6 eV) $
So, $\lambda=94.1 nm$
