Alternating Current Question 11
Question 11 - 30 January - Shift 2
In the given circuit, $rms$ value of current $(I _{rms})$ through the resistor $R$ is :
(1) $2 A$
(2) $\frac{1}{2} A$
(3) $20 A$
(4) $2 \sqrt{2} A$
Show Answer
Answer: (1)
Solution:
$z=\sqrt{100^{2}+(200-100)^{2}}$
$=100 \sqrt{2} \Omega$
$i _{rms}=\frac{V _{rms}}{z}=\frac{200 \sqrt{2}}{100 \sqrt{2}}$
$=2 A$