Three Dimensional Geometry Question 1
Question 1 - 24 January - Shift 1
The distance of the point $(7,-3,-4)$ from the plane passing through the points $(2,-3,1),(-1,1,-2)$ and $(3,-4,2)$ is :
(1) 4
(2) 5
(3) $5 \sqrt{2}$
(4) $4 \sqrt{2}$
Show Answer
Answer: (3)
Solution:
Formula: Equation Of A Plane, A Plane and A Point
Equation of Plane is
$= \begin{vmatrix} x-2 & y+3 & z-1 \\ -3 & 4 & -3 \\ 4 & -5 & 4\end{vmatrix} =0$
$x-z-1=0$
Distance of $P(7,-3,-4)$ from Plane is
$d=|\frac{7+4-1}{\sqrt{2}}|=5 \sqrt{2}$
