Solutions Question 12
Question 12 - 31 January - Shift 1
The total pressure of a mixture of non-reacting gases $X(0.6 g)$ and $Y(0.45 g)$ in a vessel is 740 $mm$ of $Hg$. The partial pressure of the gas $X$ is $mm$ of $Hg$. (Nearest Integer)
(Given : molar mass $X=20$ and $Y=45 g mol^{-1}$ )
Show Answer
Answer: (555)
Solution:
$P_X=\chi_X P_T$
$=\frac{\frac{0.6}{20}}{\frac{0.6}{20}+\frac{0.45}{45}} \times 740$
$P_X=555 mm Hg$
