Redox Reactions Question 1
Question 1 - 24 January - Shift 1
$5 g$ of $NaOH$ was dissolved in deionized water to prepare a $450 mL$ stock solution. What volume (in $mL$ ) of this solution would be required to prepare $500 mL$ of $0.1 M$ solution?
Given : Molar Mass of $Na, O$ and $H$ is 23, 16 and 1 $g mol^{-1}$ respectively
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Answer: (180)
Solution:
Formula: Molarity
$M=\frac{5}{40} \times \frac{1000}{450}$
$M_1 V_1=M_2 V_2$
$(\frac{5}{40} \times \frac{1000}{450}) \times V_1=0.1 \times 500$
$V_1=180$