Electrochemistry Question 11
Question 11 - 31 January - Shift 2
The resistivity of a $0.8 M$ solution of an electrolyte is $5 \times 10^{-3} \Omega cm$. Its molar conductivity is____________ $\times 10^{4} \Omega^{-1} cm^{2} mol^{-1}$. (Nearest integer)
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Answer: (25)
Solution:
$ \begin{aligned} \Lambda_m & =\frac{\kappa \times 1000}{M} \\ \Lambda_m & =\frac{1}{\rho} \times \frac{1000}{M} \\ & \frac{1}{5 \times 10^{-3}} \times \frac{1000}{0.8} \end{aligned} $
Ans. $25 \times 10^{4} \Omega^{-1} cm^{-2} mol^{-1}$
